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AfilCa [17]
3 years ago
9

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

in the race. Assume theâ runner's speed at the finish line is zero.
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

d=11*\frac{32}{60}\\d= 5.87\ mi

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

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The first several terms of a sequence { an } are given. Assume that the pattern continues as indicatedand find an explicit formu
solniwko [45]

Answer:

  an = 2 + n

Step-by-step explanation:

The differences between terms are all 1. The first term is 3. The general form of the general term is ...

  an = a1 + d(n -1)

Filling in a1 = 3 and d = 1, we have ...

  an = 3 + n - 1

  an = 2 + n . . . . . . simplify

4 0
3 years ago
A typical lap around a track in the United States has length of 440 yards. How many lap would need to be complete to run a mile?
g100num [7]

4 laps because a mile is 1,760 yards and the 440 laps need to be divided into 1,760 so 1,760/440 is 4 so four laps are needed to complete a mile

3 0
3 years ago
Calle had five times as many stickers as sara did and twice as many as juniper. Juniper had 25 stickers. How many stickers did t
n200080 [17]

Calle: has twice as many as Juniper so = 2*25 = 50

she also has 5 times as many as sara so if she has 50, you divide 50/5 = 10

Calle has 50 stickers, Sara has 10 and Juniper has 25.

So all together they have 85 stickers.

3 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
55.8 is 62% of what number?
zhenek [66]
90

55.8 /? = 62/100
55.8 x 100= 62 x ?
5580=62 x ?
5580/62 = ?
?=90
7 0
3 years ago
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