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AfilCa [17]
3 years ago
9

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

in the race. Assume theâ runner's speed at the finish line is zero.
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

d=11*\frac{32}{60}\\d= 5.87\ mi

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

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Solve {-20-5x}-70=-40
Artemon [7]

Answer:

x = -10

Step-by-step explanation:

6 0
3 years ago
Solve the system using the elimination method.
Sloan [31]

Answer:

x=151/64   y=9/8 z=-51/32

Step-by-step explanation:

2x+2y+5z- (2x-y+z)=-1-2

3y+4z=-3

2x+2y+5z- (2x+4y-3z)=-1-14

-2y+8z=-15

We have two equations 3y+4z=-3 and -2y+8z=-15 (We get it due to elimination method)

3y+4z=-3 (2)

-2y+8z=-15 (-3)

6y+8z=-6

6y-24z=45

(6y+8z)- (6y-24z)= -6-45

32z=-51

z=-51/32

3y-204/32=-3

3y= -96/32+204/32

3y=108/32

y=36/32=9/8

2x+2*9/8+5*(-51/32)=-1

2x+9/4-255/32=-1

2x+72/32-255/32=-1

2x-183/32=-32/32

2x=151/32

x=151/64

8 0
3 years ago
A football is kicked into the air. Its height above the ground is approximated by the equation h=20t-5<img src="https://tex.z-dn
Anastaziya [24]

Answer:

Zeroes - x=0 and x=4

Football hits the ground at x=4 (4 seconds)

Step-by-step explanation:

1) Plug equation in graphing calculator and graph function.

2) Find zeroes

3) The second zero is when the football hits the ground

4 0
2 years ago
For a trip, one high school rented and filled 8 vans and 5 buses with 196 students.
bixtya [17]

Each van can carry 12 students while each bus can carry 20 students each.

Step-by-step explanation:

Step 1; Assume x is the number of students in a van and y is the number of students in a bus. It is given that 8 vans and 5 buses are filled with 196 students in one high school. So

8x + 5y = 196, take this as equation 1.

In another high school, 216 students are fitted into 3 vans and 9 buses. So,

3x + 9y = 216, take this as equation 2.

Step 2; We multiply equation 1 with 3 and equation 2 with 8 so we can cancel out the variable x in both equations. By doing this we get

24x + 15y = 588, take this as equation 3 ,

24x + 72y = 1,728, take this is equation 4,

If we subtract equation 4 from equation `3, we cancel out the x variable and can calculate the value of y.

-57y = -1,140,

Since both sides are negative they cancel out

y = -1,140/-57 = 20.

Step 3; Substituting this value of y in any of the previous equations we will get x's value. Here this value of y is substituted in equation 1.

8x +5(20) = 196, 8x + 100 = 196 , 8x = 96, x= 12.

So we have x = 12 and y = 20.

So 12 students can fit in a van and each bus can carry 20 students.

 

3 0
3 years ago
Which of the following is a transformation of the graph y = (x - 5)^2?
S_A_V [24]
Answer: B. Shifts right 5


Explanation:

When the number after the variable is in the parentheses, the transformation will be opposite of the sign. In this problem, the sign for 5 is negative so you would be going right 5 units because right is positive so that would be the opposite of the sign.
8 0
3 years ago
Read 2 more answers
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