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AfilCa [17]
3 years ago
9

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

in the race. Assume theâ runner's speed at the finish line is zero.
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

d=11*\frac{32}{60}\\d= 5.87\ mi

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

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Find the measure of ZDCF. C F mDF = 49 G E MEG = 127 Find the measure of angle DCF​
AleksandrR [38]

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

Arc DF = 49

Solution

<DCF = 1/2(127 - 49)

<DCF = 1/2(78)

<DCF = 39

8 0
2 years ago
John is interested in purchasing a multi-office building containing five offices. The current owner provides the following proba
Elenna [48]

Answer:

Option B.

Step-by-step explanation:

The given table is:

Number of Lease Offices :  0           1         2       3        4         5

Probability                         : 5/18     1/4     1/9    1/18     2/9      1/12

The expected probability is

Expected probability = \sum_{i=0}^5 x_{i}p(x_i)

Expected probability = 0p(0)+1P(1)+2P(2)+3P(3)+4P(4)+5P(5)

Expected probability = 0\cdot (\frac{5}{18})+1\cdot (\frac{1}{4})+2\cdot (\frac{1}{9})+3\cdot (\frac{1}{18})+4\cdot (\frac{2}{9})+5\cdot (\frac{1}{12})=\frac{35}{18}

It is given that the yearly lease = $12,000.

The yearly leases for the whole building in a given year is

Yearly leases = \frac{35}{18}\times 12000=23333.3333333\approx 23333.33

Therefore, the correct option is B.

3 0
3 years ago
Please help me thanks please <br> Will give you brainlest
Akimi4 [234]

Answer:

224

Step-by-step explanation:

<u>Base:</u>

A = Bh

A = 8(8) = 64

<u>Sides:</u>

A = 1/2 Bh

A = 1/2 8(10)

A = 40

<u>Then you do 40(4) because there are 4 sides:</u>

40 (4) = 160

<u>Then you add up the base and the sides:</u>

160 + 64 = 224

(I think this is the right answer)

7 0
3 years ago
A jeweler is making a triangular pendant. He has two sides of length 23 mm and 31 mm. What are the
denis-greek [22]

Answer:

38.60mm

Step-by-step explanation:

Step one:

Given data

We are given that the dimension of the triangles are length 23 mm and 31 mm

Let us assume that the triangle is a right angle triangle

Step two:

Applying the Pythagoras theorem we can find the third as

z^2= x^2+y^2\\\\z^2= 31^2+23^2\\\\z^2= 961+529\\\\z^2= 1490\\\\

square both sides

z= √ 1490

z= 38.60mm

Hence a possible dimension of the third side is 38.60mm

3 0
3 years ago
What is:<br><br> 3✖️(-4)➗(-2) -9<br> ———————<br> (+6)
Elis [28]
The answer is - 23/6 it should be
4 0
3 years ago
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