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VikaD [51]
3 years ago
12

What is the common ratio of the geometric sequence below 625,125,25,5,1,...

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer: \frac{1}{5}

Step-by-step explanation:

In the geometric sequence we can see each time we are dividing by 5. That is the same as multiplying by \frac{1}{5} so that is the common ratio.

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Round each number to the nearest hundredth. what is the best estimate for the answer to 434.657 102.494?
Fiesta28 [93]
<span>434.657,  hundredth digit is 5, after the 5 is 7, since the 7 is more than 5, we add 1 to the hundredth digit 5, to make it become 6.

</span>434.657 ≈ 434.66   to the nearest hundreth.

102.494,  hundredth digit is 9, after the 9 is 4, since the 4 is less than 5, we the hundredth digit remains as 9.

102.494  <span>≈ 102.49  </span>to the nearest hundreth.

Hope this helps.
6 0
3 years ago
Read 2 more answers
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
1) Which circles are congruent?
alexdok [17]
Hello!

1) A and D

The radius is the distance from the center of a circle to any part of the edge. Both A and D have a radius of three, regardless of what direction they go.

2)  5"

In circle C we see that there is a line segment that is 5" that goes from the center to the edge, or the radius.

3) C

The different variables are representing different points on the circles. The circle that contains a line connecting C and L is circle C.

4) BN

Circle B contains a radius that is the distance from B to N, or BN.

5) EF

The diameter is the distance of a  straight line that was pass through the middle of a circle, or its width. The diameter is double the radius. In circle A we see that line EF passes through the center put goes all the way across the circle.

6)IJ

Line IJ isn't even linear, so it could not be the radius. Both AG and BH are straight lines that represent the radius.

7) 6"

The diameter is always twice the radius. In circle A the radius is 3, so the diameter is 6.

8) A and D

Just as we said in the first answer, A and D both have a radius that measures 3 inches.

I hope this helps!
7 0
3 years ago
Identify this conic section.<br><br> 9x 2 + 4y 2 = 36
oksano4ka [1.4K]
Divide: 9x 2/36 - 4y 2/36 = 36/36. Simplify: x2/4 - y2/9 = 1. Then do (x-0) 2/4 - (y-0)2 =1. Hyperbola.
4 0
3 years ago
Plz help me I’m begging you I will give brainliest
Rasek [7]

Answer:

80 Cubic Units

Step-by-step explanation:

5 x 4 = 20

20 x 4 = 80

Hope it helps :)

6 0
3 years ago
Read 2 more answers
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