Answer:
Option 4
Step-by-step explanation:
Term = n/(4^n)
(n+1)th term = (n+1)/[4^(n+1)]
Ratio: (n+1)/[4^(n+1)] ÷ n/(4^n)
= (n+1)/[4^(n+1)] × (4^n)/n
= [(n+1)/n] × (1/4)
For large n, (n+1)/n approaches 1
[(n+1)/n] × (1/4) approaches 1/4 which is less than 1
Since the ratio is less than 1, series converges
