Question

What is the diameter of the circle whose center is at (6,0) and passes through the point (2,-3)

Answer 1

10 units!!! (X1,Y1)= 6,0 and (X2,Y2)= (2,-3)

Answer 2

Answer: 10 units

Step-by-step explanation:

Use the distance formula(√(x1-x2)^2+(y2-y1)^2)

$\sqrt{(6-2)^2+(0-(-3))^2} \\\\\sqrt{4^2+3^2}\\\\\sqrt{16+9}\\ \\\sqrt{25}\\ \\5$

Thus, the radius of the circle is 5.  Because the diameter is 2r, the diameter = 2(5) = 10

Hope it helps <3