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3 years ago

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If 3/4 of an inch of rain fell in 1/2 hour, explain how to get the unit rate

1 answer:

bearhunter [10]3 years ago

4 0

Answer:

Search to find the detailed rainfall collections if you want more detailed rainfall intensity data. If all available is monthly average in mm, take the monthly average and divide by number of hours in that month. So if you had 300 mm in April, take 360 mm/(30 days * 24 hours) = 0.5 mm/hour average monthly intensity. so that's it

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Write the equation in slope-intercept form that contains the following two points.

viva [34]

Answer:

y = -3/2 x +5

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

m= (8--1)/(-2-4)

m= (8+1)/(-2-4)

m= (9/-6)

m=-3/2

point slope form

y-y1=m(x-x1)

y--1 = -3/2(x-4)

distribute

y+1 = -3/2x +3/2 *4

y+1 = -3/2x + 6

subtract 1 from each side

y = -3/2 x +6-1

y = -3/2 x +5

this is in slope intercept form (y=mx+b)

6 0

3 years ago

Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is $\dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1$

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes are $y = k \pm \dfrac{b}{a}(x - h)$

1. Calculate h and k. The hyperbola is symmetric about the origin, so

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3

3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

$\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}$

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0

3 years ago

Meagan has 1200 sugar cubes. What is the largest sugar cube she could build with the sugar cubes.

IgorLugansk [536]

Can you explain this question more please

4 0

3 years ago

Create an equation that describes the greatest horizontal length, H, in terms of the greatest vertical length, V.

marishachu [46]

The equation that describes the greatest horizontal length, H, in terms of the greatest vertical length, V is H = 2V + 3.

<h3>How to compute the equation?</h3>

Your information is incomplete. Therefore, an overview will be given.

Let's assume that the value of the horizontal length is 3 plus twice the value of the the vertical length. This will be:

H = (2 × V) + 3

H = 2V + 3

In conclusion, the equation is H = 2V + 3.

Learn more about equations on:

brainly.com/question/2972832

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%3D%203x%2B1%20%2C%20g%28x%29-%202x%20-1" id="TexFormula1" title="f(x)= 3x+1 , g(x)- 2

Bond [772]

Answer:

(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)

8 0

3 years ago