*The complete question is in the picture attached below.
Answer:
756πcm³
Step-by-step Explanation:
The volume of the solid shape = volume of cone + volume of the hemisphere.
==> 270πcm³ + ½(4/3*π*r³)
To calculate the volume of the hemisphere, we need to get the radius of the hemisphere = the radius of the cone.
Since volume of cone = 270πcm³, we can find r using the formula for the volume of cone.
==> Volume of cone = ⅓πr²h
⅓*π*r²*10 = 270π
⅓*10*r²(π) = 270 (π)
10/3 * r² = 270
r² = 270 * ³/10
r² = 81
r = √81
r = 9 cm
Thus, volume of hemisphere = ½(4/3*π*r³)
==> Volume of hemisphere = ½(⁴/3 * π * 9³)
= ½(972π)
Volume of hemisphere = 486πcm³
Volume of the solid shape
= volume of cone + volume of the hemisphere.
==> 270πcm³ + 486πcm³
= 756πcm³
Step-by-step explanation:
ABC+DAB=180
DAB=180-115
DAB= 65
m<3+m<4=65
m<3=65-m<4
You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.
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Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.
Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:
The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.
Thus, the lowest score of test A is given by 40(21) + 50 = 890
Therefore, the lowest score of test A is 890.
Part B:
The mean score is a measure of location, so both
addition and multiplying the mean score of test B by 40 and adding 50
to the result will affect the lowest score of test A.
Thus, the mean score of test A is given by 40(29) + 50 = 1,210
Therefore, the mean score of test A is 890.
Part C:
The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50
to the result will not affect the standard deviation of test A.
Thus, the standard deviation of test A is given by 40(2) = 80
Therefore, the standard deviation of test A is 80.
Part D
The Q3 score is a measure of location, so both
addition and multiplying the Q3 score of test B by 40 and adding 50
to the result will affect the Q3 score of test A.
Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170
Therefore, the Q3 score of test a is 1,170.
Part E:
The median score is a measure of location, so both
addition and multiplying the median score of test B by 40 and adding 50
to the result will affect the median score of test A.
Thus, the median score of test A is given by 40(26) + 50 = 1,090
Therefore, the median score of test A is 1,090.
Part F:
The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50
to the result will not affect the IQR of test A.
Thus, the IQR of test A is given by 40(6) = 240
Therefore, the IQR of test A is 240.
Answer:
Is x = 4 a solution to the equation 6 = x + 2? YES
Is x = 4 a solution to the inequality 2x ≥ 9? NO
Step-by-step explanation:
Is x = 4 a solution to the equation 6 = x + 2? YES
we cans solve the equation 6=x+2 by clearing for x:
6 = x + 2
we move the +2 on the right as a -2 to the left:
6 - 2 = x
4 = x
this way we find that indeed x = 4 is a solution to 6 = x + 2.
Is x = 4 a solution to the inequality 2x ≥ 9? NO
Let's solve the inequality by clearing for x:
2x ≥ 9
we move the 2 that is multiplying on the left to divide on the right side:
x ≥ 9/2
x ≥ 4.5 ⇒ <u>x must be greater than or equal to 4.5</u>
thus, <u>4 is not a solution to the inequality</u> because 4 is less than 4.5
