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2 years ago

Please help me with this

Mathematics

2 answers:

Sever21 [200]2 years ago

5 0

Answer:

$\begin{array}{c|c}x&y\\-2&13\\-1&9\\0&5\\1&1\\2&-3\end{array}$

Step-by-step explanation:

Put x = -2, x = -1, ... , x = 2 to the equation of the function y = -4x + 5 and calculate the values of y:

for x = -2

y = -4(-2) + 5 = 8 + 5 = 13

for x = -1

y = -4(-1) + 5 = 4 + 5 = 9

for x = 0

y = -4(0) + 5 = 0 + 5 = 5

for x = 1

y = -4(1) + 5 = -4 + 5 = 1

for x = 2

y = -4(2) + 5 = -8 + 5 = -3

forsale [732]2 years ago

5 0

Just put the values given for x in the equation to find y

-4(-2)+5=13

-4(-1)+5=9

-4(0)+5=5

-4(1)+5=1

-4(2)+5=-3

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Podcza

7 0

2 years ago

Look at the data set below:

Elenna [48]

Median: Sort from least to greatest and find the # in the middle.
Sort: 54, 58, 58, 60, 62.
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Mode: 58, because it appears most.
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If you want to find the mean, then here:
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6 0

2 years ago

Read 2 more answers

Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in s

vagabundo [1.1K]

Answer:

y = -0.2x - 5.8

Step-by-step explanation:

If a line is given in the form y = mx + b, the "m" is the slope.

For the line given y = 5x, the slope is 5

The line that is perpendicular to this will have slope that is "negative reciprocal of that".

So, the perpendicular line will have slope of $-\frac{1}{5}$

So, the Perpendicular Line will have equation:

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Let's find b by replacing x with 6 and y with -7 [the point given]. So we have:

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3 years ago

Use proper probability notation. Identify function and label inputs when using technology.

zhannawk [14.2K]

Answer:

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Step-by-step explanation:

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2 years ago

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Over [174]

Check the picture below, so let's check the equations below hmmm

$\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill$

$\boxed{D}\\\\ y+4=2x\implies y=2x\underset{\stackrel{\uparrow }{b}}{-4}\qquad \textit{\Large \checkmark}\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

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