Please help me with this

Mathematics

2 answers:

Sever21 [200]3 years ago

5 0

Answer:

$\begin{array}{c|c}x&y\\-2&13\\-1&9\\0&5\\1&1\\2&-3\end{array}$

Step-by-step explanation:

Put x = -2, x = -1, ... , x = 2 to the equation of the function y = -4x + 5 and calculate the values of y:

for x = -2

y = -4(-2) + 5 = 8 + 5 = 13

for x = -1

y = -4(-1) + 5 = 4 + 5 = 9

for x = 0

y = -4(0) + 5 = 0 + 5 = 5

for x = 1

y = -4(1) + 5 = -4 + 5 = 1

for x = 2

y = -4(2) + 5 = -8 + 5 = -3

forsale [732]3 years ago

5 0

Just put the values given for x in the equation to find y

-4(-2)+5=13

-4(-1)+5=9

-4(0)+5=5

-4(1)+5=1

-4(2)+5=-3

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The team ran

juin [17]

The team ran 2 miles.

Step-by-step explanation:

Step 1; The track is $\frac{3}{4}$ miles long and the team ran 2 $\frac{2}{3}$ laps on it. To calculate the distance run we multiply the number of laps ran with the distance on each lap.

Distance run = Number of laps × Distance on each lap.

Step 2; We convert 2 $\frac{2}{3}$ from a mixed fraction into an improper fraction. To do this, we multiply the whole number with the denominator of the fraction and add with it the numerator of the same fraction whereas the denominator remains unchanged. To convert the fraction 2 $\frac{2}{3}$ = ((2 × 3) + 2) / 3 = $\frac{8}{3}$ .