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3 years ago

What is the absolute value of -4-2i

2 answers:

6 0

The absolute value of an integer is the numerical valuewithout regard to whether the sign is negative or positive. On a number line it is the distance between the number and zero. Absolute value is also known as magnitude.

Mariulka [41]3 years ago

4 0

I think the answer would be 4+2i.

All absolute value is asking is how far away it is from zero.

You might be interested in

What are the coordinates of the point that is one half the distance between A(-1, -2) and B(6, 12)?

MA_775_DIABLO [31]

The coordinates of the point that is one-half the distance between A(-1,-2) and B(6,12) is (2.5,5)

What is the midpoint?

The mid-point lies midway between the two ends. Its x value lies in the middle of the other two x values. Its y value lies in the middle of the other two y values.

Given, $A(6,12) = (x_{1}, y_{1} )$

$B(6,12) = (x_{2}, y_{2} )$

Let M is a midpoint of AB, then

$M(x,y)=(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1} +y_{2}}{2} )= (\frac{-1+6}{2} ,\frac{-2+12}{2} )=(2.5,5)$

The midpoint of point AB is M(2.5,5)

Therefore, the coordinates of the point which is one-half the distance between A(-1,-2) and B(6,12) is M(2.5,5).

To learn more about the midpoint

brainly.com/question/24676143

#SPJ1

5 0

1 year ago

The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon

Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

$\bf P(t)= Ce^{kt}$

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

$\bf P(t)= 10.3e^{kt}$

Given that P(10)=12.5

$\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936$

And the function that models the population growth is

$\bf P(t)= 10.3e^{0.01936t}$

We need P(20)

$\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million$

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0

3 years ago

What is the probability

vovangra [49]

True is the answer imo

5 0

3 years ago

Read 2 more answers

The cost of parking a motor home in a state park includes a one time fee of $180, plus a daily rate of $55 per day. Anthony prep

HACTEHA [7]

Answer:

Anthony paid for 7 days of parking.

Step-by-step explanation:

From the information given, the cost of parking a motor home in a state park would be equal to the one time fee plus the result of multiplying the daily rate for the number of days:

c=180+55x, where c is the cost of parking the motor home and x is the number of days.

Now, you can replace c with 565 that is the amount Anthony prepaid and you can solve for x to be able to find the number of days he paid for:

565=180+55x

565-180=55x

385=55x

x=385/55

x=7

According to this, Anthony paid for 7 days of parking.

7 0

3 years ago

Please help!! Question is in the picture!!

Debora [2.8K]