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-BARSIC- [3]
3 years ago
11

I need help on this question ASAP

Mathematics
1 answer:
Kipish [7]3 years ago
7 0
R>-6
Please correct me if I’m wrong
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Given the right triangle shown below, prove cos2(θ) + sin2(θ) = 1.
wel

Answer:

-definition of cosine

-definition of sine

-Pythagorean Theorem

-Substitution

-laws of exponents

Step-by-step explanation:

3 0
4 years ago
The sparky valley barbershop quartet made appearances in Quakertown and Doleystown. The hotel charge before taxes in Doleystown
joja [24]

Answer:

The hotel at Qakertown charged $5000 before tax while the hotel at Doleystown charged $5,500 before tax

Step-by-step explanation:

In this question, we have a musical band that visited two different towns which hotel charge different amounts at different tax rate. We are now given the total amount in taxes and now asked to calculate what is charged in each of the towns.

Let’s proceed!

Since we do not know the amount charged in each of the towns, let the amount charged at the hotel at Quakertown be $x and the amount charged at the hotel at Doleytown be $y.

Doley charged $500 more then what is charged at Quaker.

Mathematically;

y = 500 + x •••••••••••••••(I)

Let’s now work with the taxes;

Tax rate at Doley is 6% or say 0.06; the amount of tax paid at Doley is thus 0.06y

Tax rate at Quaker is 3% or say 0.03; the amount of tax paid at Quaker is thus 0.03x

Mathematically;

0.06y + 0.03x= 480 •••••••••(ii)

We can substitute i into ii

0.06(500 + x ) + 0.03x = 480

30+ 0.06x + 0.03x = 480

30 + 0.09x = 480

0.09x = 480 - 30

0.09x = 450

x = 450/0.09

x = $5,000

y = 500 + x

y = 500 + $5000 = $5,500

5 0
3 years ago
Surface-finish defects in a small electric appliance occur at random with a mean rate of 0.3 defects per unit. find the probabil
mario62 [17]

Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

Step-by-step explanation:

Since we have given that

Mean rate defects per unit = 0.3

Since we will use "Poisson distribution":

P(X=K)=\frac{e^{-\lambda}\lambda^k}{k!}

But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.

P(X\geq 2)=1+P(X=0)+P(X=1)

So,

P(X=0)=\frac{e^{-0.3}0.3^0}{0!}=e^{-0.3}=0.74\\\\P(X=1)=\frac{e^{-0.3}\times 0.3}{1}=0.22

so, it becomes,

P(X>2)=1-(0.74+0.22)=1-0.96=0.04

Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

4 0
4 years ago
Complete <br> Solve 2x2 + x − 4 = 0
Svetradugi [14.3K]

Step-by-step explanation:

2 x 2 + x - 4 = 0

4 + x - 4 = 0

<u>+</u><u>4</u> <u>+4</u>

8 0

<u>8</u> + x = <u>0</u>

8 8

x = 0

For the - 4 + 4 part, it cancels out because it's 0 and for the 8 divided by 8 part, it cancels out too. x is 0 because 0 divided by 8 is 0.

Hope this helped!

7 0
3 years ago
Read 2 more answers
Please Help<br> Solve for X<br> 22x - 74
Murljashka [212]
22x-74=0
+74 +74
22x=74
X= 3.36 repeating
7 0
3 years ago
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