Answer:
The distance of the plane from the base of the tower is 25.5 foot.
Step-by-step explanation:
As given
Max is in a control tower at a small airport.
He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.
Now by using the trigonometric identity.

As shown in the figure given below
Perpendicular = CB
Base = AC = 50 feet

Put in the identity.



Put in the above

CB = 0.51 × 50
CB = 25.5 foot
Therefore the distance of the plane from the base of the tower is 25.5 foot.
Answer:
130° is the correct answer
∠QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°
Hi there!
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I believe your answer is:
c < 2
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Here’s why:
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Hope this helps you. I apologize if it’s incorrect.
I think the answer is 1.125