Answer:
speed while going = 42, while returning home = 28
Step-by-step explanation:
let his speed on the way to his parents house is (x)
then his speed while returning is x - 14
Time = Distance / speed
528 / x + 528 / x -14 = 22
multiplying the denominator ...
528x + 528x +7392 = 22x^2 +14x
1056x + 7392 = 22x^2 + 308x
0 = 22x^2 -748x -7392
"dividing by 22"
0 = x^2 -34x-336
0 = (x+8) (x-42)
x must be 42
finally jon's speed while back home is 42 - 14 = 28
Answer:
A. 312
Step-by-step explanation:
I answered this on another post
Answer:
0.25D^2 π in^2.
Step-by-step explanation:
The cross section is a circle of diameter D inches, so its radius is 0.5D inches.
The area of cross section is πr^2
= (0.5D)^2 π
= 0.25D^2 π in^2.
Answer:
-18
Step-by-step explanation:
Solution:
we have been asked to find
The smallest value of n such that the LCM of n and 15 is 45.
The prime factors of 15 are
So in LCM of n and 15 , we must include both the prime factors and the LCM is 45.
Since 3 is one time in the prime factor of 15. But to make 45 we need one more 3 and its possible if we take the value of n as below"
n=9
Hence the LCM will be
Hence the smallest possible value of n is 9.
