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dem82 [27]
3 years ago
12

Find the net change in the value of the function between the given inputs. h(t) = t2 + 2; from −5 to 8

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

39

Step-by-step explanation:

Given the function :

h(t) = t² + 2

From t = 5 to t = 8

when, t = 5

h(5) = 5² + 2

h(5) = 25 + 2

h(t) at t = 5 ; equals 27

when, t = 8

h(5) = 8² + 2

h(5) = 64 + 2

h(t) at t = 8 ; equals 66

Net Change :

h(8). - h(5)

66 - 27 = 39

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When a number is added to of itself, the result is 24. The equation that models this problem is n + n = 24. What is the value n?
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Well we know that what N stands for is 2 times N = 24 so we should do 24/2 =12 so the answer is N=12
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If a car can travel 50 miles in 55 minutes how long will it take to travel 75 minutes
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50/55= x/75
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I need help! Find the equation of a line parallel to 3x-3y=5 that contains the point (-1,-5). Write the equation in slope Interc
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the equation of the line is y= x-4

Step-by-step explanation:

so so the first thing that you're going to do is get y alone

-x-5=y

next you're going to find your slope which in this case is negative one.

after that in order to find the equation of a parallel line you're going to find the reciprocal of the slope.

so in this case the reciprocal is one.

next you're going to substitute in the cordinates to find the y intercept

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6 0
4 years ago
Boat A is 20 km from port on a bearing of 025° and boat B is 25 km from port on a bearing of 070°. Boat B is in distress. What b
tiny-mole [99]

Answer: Boat A should travel 152.8° to reach B

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo. Triangle ABP is formed. A represents the position of boat A. B represents the position of boat B. P represents the position of the port.

We would determine AB by applying the law of cosines

AB² = AP² + BP² - 2AP×BPCosP

AB² = 20² + 25² - 2 × 20 × 25 × Cos45

AB² = 1025 - 707.10678 = 317.89322

AB = √317.89322 = 17.83

We would determine the bearing of B from A by finding angle A. We would apply the sine rule.

AB/SinP = AP/Sin A

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17.83 × SinA = 20Sin45 = 14.14

SinA = 14.14/17.83 = 0.79

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The total angle at A is 65 + 52.2 = 117.2°

The angle formed outside the third quadrant is 117.2 - 90 = 27.2°

Therefore, bearing B from A is

180 - 27/2 = 152.8°

3 0
3 years ago
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