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ololo11 [35]
4 years ago
6

5x - 11 " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anon25 [30]4 years ago
7 0
8x + 4 = 5x - 11

Subtract 5x from both sides:
3x + 4 = -11

Subtract 4 from both sides:
3x = -15

Divide both sides by 3:
x = -5

Answer : x = -5
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Identify the dependent variable in the statement: the quality of a public school teacher and the amount of student learning.
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Dependent variables are something that depends on other factors. therefore, if the quality of the public school teacher is poor, it will affect the student's learning badly, and if the teacher's teaching is strong, it affects the student's learning greatly. The student's learning depends on how well the teacher teaches.
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A recipe for cake calls for 3 cups of flour and
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Answer:

1/2 a cup of water

Step-by-step explanation:

4 0
3 years ago
If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the ne
stiv31 [10]

Answer: 7.93

Step-by-step explanation:

Given

f(x) is an exponential function. Suppose f(x) is ae^{bx}

f(1.5)=5\ \text{and}\ f(7.5)=79

\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)

Similarly,

\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)

Subtract (i) and (ii)

\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066

Insert the value of b

\Rightarrow 5=ae^{0.46}\\\Rightarrow a=5\times 0.6312\\\Rightarrow a=3.156\approx 3.16

So, the function becomes

\Rightarrow f(x)=3.16e^{0.3066b}

\Rightarrow f(3)=3.16e^{0.3066\times 3}\\\Rightarrow f(3)=7.927\approx 7.93

4 0
3 years ago
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Which of the following statements best describes the graph of x + y = 3?
inysia [295]
Its a line joining the points whose x and y coordinates add up to 3
6 0
3 years ago
Read 2 more answers
Please help me.i don't get it.
alukav5142 [94]

Answer:

See below.

Step-by-step explanation:

The addition method is a good choice in this case since you have x in one equation and -x in the other equation, and x and -x add to zero, eliminating x.

 x - 5.5y = -14

-x + 2.6y = 8.2

Add the equations. x and -x ad to zero, eliminating x. Then solve for y.

-2.9y = -5.8

Divide both sides by -2.9

y = 2

Substitute 2 for y in the first original equation, and solve for x.

x - 5.5y = -14

x - 5.5(2) = -14

x - 11 = -14

x = -3

Solution: x = -3; y = 2

Since the coefficients of y in the two original equations are not opposites, the addition method would not be the best method to use to solve for y first.

4 0
2 years ago
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