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nikitadnepr [17]

3 years ago

10

Glenda began the day with a golf score of -6 and ended with a score of -10. Which statement represents her golf score for that d

ay?
A) -6 - ( - 10) = 4

B) - 10 - ( - 6) = - 4

C) - 6 + ( - 10) = - 16

D) - 10 + ( - 6) = - 16

2 answers:

Maksim231197 [3]3 years ago

6 0

B. I need 20 characters to answer so I hope you have a wonderful day

dalvyx [7]3 years ago

3 0

B)
She started with -6 and ended up with -10 so her score was 4 less than what she started with so it is -4

You might be interested in

Graphs and equations of lines

dmitriy555 [2]

Answer:

a) $y = -\frac{3}{4} x + 5$

b) $y = 6x-18$

c) $y = \frac{4}{5} x+\frac{19}{5}$

Step-by-step explanation:

a) The slope / gradient is the coefficient of $x$ , so for a) it will be $y=-\frac{3}{4} x + C$ .

C is the y-intercept, so the full equation will be $y = -\frac{3}{4} x + 5$ .

b) Again, since the slope is 6, we know the coefficient of $x$ will be 6.

Now, we have a point on the line and so far, we know the equation is $y=6x+c$ . The coordinates of the point are (2,-6). So now we substitute the y and x values into the equation in order to find C.

$-6 = 6(2)+C$

$-6 = 12+C$

$C = -18$

$y = 6x-18$

c) To find the gradient we must use the formula $\frac{rise}{run}$ .

rise = change in y value

run = change in x value

so, the gradient $= \frac{7-3}{4-(-1)} = \frac{4}{5}$

Now the equation is $y = \frac{4}{5} x +C$

Again, to find C we substitute any of the coordinates into the equation. I will use (-1,3).

$3 = \frac{4}{5} (-1) +C$

$3 + \frac{4}{5} =C$

$C =\frac{19}{5}$

so c) is $y = \frac{4}{5} x+\frac{19}{5}$

6 0

3 years ago

Which expression could be used to determine the reduction of -4 and 3 1/4

Setler79 [48]

Answer:

The expression that could be used is (-4)(3) + (-4)( $\frac{1}{4}$ ) ⇒ B

Step-by-step explanation:

Let us revise the distributive property:

<em>The product of a number and the sum of 2 other numbers equal to the sum of the products of the number with the other 2 numbers</em>

a(b + c) = ab + ac

We will use this rule to solve the question

∵ The product of -4 and 3 $\frac{1}{4}$ = -4 × 3 $\frac{1}{4}$

→ We can right 3 $\frac{1}{4}$ as (3 + $\frac{1}{4}$ )

∵ 3 $\frac{1}{4}$ = (3 + $\frac{1}{4}$ )

∴ -4 × 3 $\frac{1}{4}$ = -4(3 + $\frac{1}{4}$ )

→ By using the rule above

∵ -4(3 + $\frac{1}{4}$ ) = (-4)(3) + (-4)( $\frac{1}{4}$ )

∴ -4 × 3 $\frac{1}{4}$ = (-4)(3) + (-4)( $\frac{1}{4}$ )

∴ The expression that could be used is (-4)(3) + (-4)( $\frac{1}{4}$ )

3 0

3 years ago

The hourly wages earned by 20 employees are shown in the first box-and-whisker plot below. The person earning $15 per hour quits

agasfer [191]

Answer:

<h2>The mean decreases, and the median remains the same.</h2>

Step-by-step explanation:

Remember that a box plot is made by the quartiles of the distribution, the maximum value and the minimum value. So, from a box plot we can deduct the range, the median and the interquartile range.

In this case, the median remains the same at $9.5 per hour. The median is indicated by the middle line of the box, and you can observe that it doesn't change.

Now, the range of the data set decreases from 7 to 3.

On the other hand, the mean must decrease, because data greater than $11 doesn't exist in the box plot number 2, and the mean is a central measure sensible to those changes.

Therefore, the right answer is <em>The mean decreases, and the median remains the same.</em>

8 0

3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

A cuboid with dimensions 45 cm by 16 cm by 12 cm is cut to form smaller cubes of

LenKa [72]

Answer:

<u>135 cubes</u>

Step-by-step explanation:

Volume of cuboid :

45 x 16 x 12
720 x 12
8,640 cm³

Volume of a small cube :

(4)³
64 cm³

Number of cubes :

n = 8,640/64
n = <u>135 cubes</u>

4 0

2 years ago