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2 years ago

System of quadratic x² - y² = 4 x² + y² = 4

Mathematics

1 answer:

const2013 [10]2 years ago

5 0

Answer: (2,0),(−2,0)

Step-by-step explanation:

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PLEASE HELP ME

natulia [17]

Answer:

Broker1 with $66.

Broker2 with $54.25

Broker4 with $50

Broker3 with $47.5

Broker5 with $33.5

Explanation :

Total number of shares Cindy have : 300

Market Price per share : $25

Total price for the shares : 300 $\times$ $25

= $7500

Now ,

Case 1:

Commission provided by broker1 = 0.75%

Online fees provided by broker1 = $ 10

Total price provided by broker1= $\frac{75}{10000}\times7500 +$10$

=$66.25

Case 2:

Commission provided by broker2= 0.5%

Online fees provided by broker2=$17

Total price provided by broker2= $\frac{5}{1000}\times 7500 + $17$

=$54.5

Case 3:

Commission provided by broker 3= 0.6% for 100 0r few

Not applicable because the total shares are 300

For over 100 shares

Commission provided= 0.5%

Online fees = $10

Total price = $\frac{5}{1000}\times 7500 + $10$

=$47.5

Case 4:

For more than 100 shares

Online fees for buying and sharing= $50

Total price = $50

Case5 :

Commision for a share bought or sold = 0.05%

Online fees =$30

Total Price= $\frac{5}{10000}\times 7500 + $30$

=$33.75

6 0

2 years ago

Read 2 more answers

Is f(x)=3/4 a function?

Marat540 [252]

Answer:

Yes, f(x) = $\frac{3}{4}$ is a constant function.

Step-by-step explanation:

A function is defined to be a relation from 1 set of numbers to another set of numbers.

The main condition for a relation to be a function is that for every number in the domain there should be a unique image

Here the given function is f(x) = $\frac{3}{4}$

This function is a constant function and gives the value 0.75 for all values of x.

Hence the graph would be a straight line parallel to the x-axis passing through y = 0.75.

Hence the f(x) = 0.75 is a function.

4 0

3 years ago

Draw a box plot for the following data. {35, 50, 50, 48, 48, 32, 38, 41, 48, 34, 29, 23, 41, 34, 43}

loris [4]

I can't really draw one, but the points would be, 23,34,41,48,50

7 0

3 years ago

21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

3 0

3 years ago

What is the value of the x variable in the solution to the following system of equations?

harkovskaia [24]

Its A. x=4

procedure: 3*equation1 - 2*equation2 ⇒ x=4

8 0

3 years ago