4 wnd 6 have 2 in common factors
Answer:
1. D
2. B
3. A
Step-by-step explanation:
Question 1:
The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.
Question 2:
Given that <KLM = x°
<KML = 50°
<JKL = (2x - 15)°
According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.
2x - 15 = x + 50
Solve for x
2x - x = 15 + 50
x = 65
Therefore, <KLM = 65°
QUESTION 3:
<JKL = 2x - 15
Plug in the value of x
<JKL = 2(65) - 15
= 130 - 15
<JKL = 115°
Answer:
(x - 4)(x + 3)
Step-by-step explanation:
Given
x² - x - 12
Consider the factors of the constant term (- 12) which sum to give the coefficient of the x- term (- 1)
The factors are - 4 and + 3, since
- 4 × + 3 = - 12 and - 4 + 3 = - 1, then
x² - x - 12 = (x - 4)(x + 3) ← in factored form
Slope = Δy / Δx
11-8
--------
5-4
=
3
----
1
= 3
9514 1404 393
Answer:
v = 3/w
Step-by-step explanation:
"V varies inversely with w" means v is proportional to 1/w (the inverse of w). The usual equation for proportionality applies.
y = kx . . . . y is proportional to x
v = k(1/w) . . . . v is proportional to the inverse of w (varies inversely with w)
If you multiply this equation by w, you get ...
vw = k
Using the given values, ...
(6)(1/2) = k = 3
Then the desired equation is ...
v = 3/w