Find two consecutive even integers such that twice the smaller is 16 more than the larger
2 answers:
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(X-3)^2+5=14
Step 1: simplify both sides of the equation
X^2-6x+14=14
Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0
For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0
Step 3: Use quadratic formula with a=1, b=-6, c=0
The answer is x=6 or x=0
Step 1: simplify both sides of the equation
X^2-6x+14=14
Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0
For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0
Step 3: Use quadratic formula with a=1, b=-6, c=0
The answer is x=6 or x=0
Answer:
Vertex form.
Step-by-step explanation:
You are talking about the vertex form for a parabola.
tells us:
A) The vertex is (h,k).
B) Open up (if a is positive) or open down (if a is negative)
C) a also tells us how much it is vertically stretched or compressed.