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2 years ago

Find two consecutive even integers such that twice the smaller is 16 more than the larger

2 answers:

6 0

Define x:
Let one of the numbers be x.
The other number is x + 2

Construct equation:
twice the smaller is 16 more than the larger
⇒2x = x + 2 - 16

Solve x:
2x = x + 2 - 16
x = -14

Find the two numbers:
Smaller number = x = -14
Larger number = x + 2 = -12

Answer: The two numbers are -14 and -12

jarptica [38.1K]2 years ago

5 0

Let's make an equation. X will be the smaller number while y is the bigger.
x+2=y; since they're consecutive even numbers. We will use that equation to represent y.
Twice the smaller; 2x
16 more than the larger; 16+x+2
2x=16+x+2; let's add like terms.
2x=18+x
Let's subtract x from both sides.
x=18
If the smaller number is 18, the bigger number is 20.

The two numbers are 18 and 20.

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3 years ago

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Reptile [31]

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Step-by-step explanation:

Given function is $f(x)=480(0.3)^x$ and we need to find average rate of change of the function from $x=1\ to\ x=5$ .

Average rate of change $=\frac{f(b)-f(a)}{b-a}$

So,

$here\ b=5\ and\ a=1\\f(5)=480(0.3)^5\\=480\times0.00243=1.1664\\and\\f(1)=480(0.3)^1\\=480\times0.3=144$

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$=\frac{f(b)-f(a)}{b-a}\\\\=\frac{f(5)-f(1)}{5-1}\\\\=\frac{1.1664-144}{5-1}\\\\=\frac{-142.8336}{4}= -35.7084$

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