You have to include a drawing that relates the distace between de towers and some angles.
I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.
This lets you calculate the distance between the towers, d, as
tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft
The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.
Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft
Answer: 366.29 ft
Answer:
( 0 < y < 23 / 6 ) mins
Step-by-step explanation:
Solution:-
We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.
The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:
( 0 < x < 4 ) minutes
Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

The time taken by Jo Anne to complete her speech in English class can be represented as:
y = x - 1/6
Using the range of time that Jo Anne could take in delivering her speech in the class would be:
0 < x < 4
0 - 1/6 < y < 4 - 1/6
-1/6 < y < 23 / 6
Since time can not be less than zero. We correct the lower limit to " 0 " as follows:
( 0 < y < 23 / 6 ) mins
Answer:
y = -1/2x + (-1)
Step-by-step explanation: