Answer:
42−{(7+14)÷7}×4
42 - { 21/7} x 4
42 - 3 x 4
42 - 12
30
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Answer:
120 cm²
Step-by-step explanation:
From the question;
- Length is 12 cm
- Width is 10 cm
We are required to determine the area of the cross section;
- Note that the cross section is the plane of a solid that remains constant through the solid.
- In this case, the cross section is a rectangle whose dimensions are 12 cm by 10 cm.
But Area of a rectangle = Length × Width
Therefore;
Area of cross section = 12 cm × 10 cm
= 120 cm²
Thus, area of the cross section is 120 cm²
3/7 top and bottom are divisible by 12
Here, A.P. is 3x-1, 4x, 5x+1, 4
i) Common difference (d)
(5x-1) - 4x = x - 1
It would be same as 4 - (5x-1) = 4-5x+1 = 5-5x
Now, x - 1 = 5 - 5x
5x + x = 5 + 1
6x = 6
x = 6/6
x = 1
So, Common difference would be 1
ii) Eight term will be: a + (n-1)d = 2 + (8-1)2 = 2+7(2) = 2+14 = 16
So, eight term would be 16
Hope this helps!
Answer: 7x^2 + 2x + 7
Step-by-step explanation:
Combine likes terms that have alike variables and alike exponents.
(3x^2 + 4x^2) + (2x) + (2 + 5)
7x^2 + 2x + 7
