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vekshin1
3 years ago
12

Monica went shopping for holiday presents. She bought boxes of chocolates and boxes of ornaments for her

Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0
She can buy 6 boxes of chocolates
and 8 boxes of ornaments
6*10=60 & 8*12=96
so you would add them and get
60+96=156
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Create a word problem with 3x = 42!
Delicious77 [7]
There are 42 kids in one classroom. They are all divided into 3 groups. How many kids will be in each group?
4 0
3 years ago
Read 2 more answers
For the function f(x) = x2 ­ -12, find (f o f­-1)(4) A. 0 B. 4 C. 10 D. 6
slega [8]

We actually don't need to do any computation. By definition, the inverse function f^{-1} changes the role of input and output. So, if a function f maps x onto y, the inverse function maps y onto x.

You have to think like this: if the function makes a step further, the inverse function makes that same step back.

This means that the composition f \circ f^{-1} is always the identity function f(x) = x. In fact,

(f\circ f^{-1})(x) = f(f^{-1}(x)) = x

So, for every function, you have

(f\circ f^{-1})(4) = f(f^{-1}(4)) = 4

5 0
2 years ago
A farmer has 20 boxes of eggs
aliina [53]
I guess that is 1:10
Hope ur help !;(
5 0
3 years ago
The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?
hammer [34]
\bf \textit{circumference of a semi-circle}\\\\
C=\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
C=5.14
\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\
-------------------------------\\\\
\textit{area of a semi-circle}\\\\
A=\cfrac{\pi r^2}{2} \implies A=\cfrac{\pi }{2}r^2\implies A=\cfrac{\pi }{2}\left( \boxed{\cfrac{5.14}{\pi }} \right)^2
\\\\\\
A=\cfrac{\pi }{2}\implies \cfrac{5.14^2}{\pi ^2}\implies A=\cfrac{26.4196}{2\pi }\implies A=\cfrac{13.2098}{\pi }
5 0
2 years ago
Help.....................
eduard

Answer:

Answers in Explanation

Step-by-step explanation:

First Question:

\sqrt{100} + [18 ÷ 3 x 4 - 15] - (60 - 7^2 - 1)

\sqrt{100} + [24 - 15]  - (60 - 49 - 1)

\sqrt{100} + 9 - 10

10 + 9 - 10

<u>Answer = 9</u>

Second Question:

5x + 2x = 7x

5x^2 + 3x^2 = 8x^2

2x + 3x - x = 4x

2x + 3y + x + y = 3x + 4y

9x - 6x = 3x

-7y + 3x + 4x + 3y = 7x - 4y

-7x^2 + 2x^2 + 9x^2 = 8x^2

(3x^2 + 5x + 4) - (-1 + x^2) = 2x^2 + 5x + 5

(3 + 2x - x^2) + (x^2 + 8x + 5) = 10x + 8

(3x - 4) - (5x + 2) = -2x - 6

(2x^2 + 5x + 3) - (x^2 - 2x + 3) = x^2 + 7x

(3x^2 + 2x - 5) - (2x^2 - x - 4) = x^2 + 3x - 1

Third Question:

17x + 2y

(5x + 12y) + (3x + y) = 8x + 13y

17x - 8x = 9x

2y - 13y = -11y

Answer: 9x - 11y

7 0
2 years ago
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