Answer: equation of the tangent plane is z = 1
Step-by-step explanation:
Given equation
z = e^(-x²-y²) at point (0,0,1)
now let z = f(x,y)
Δf(x,y) = [ fx, fy ]
= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))
now
Δf (0,0) = [ 0, 0 ] = [ a, b ]
equation of the tangent plane therefore will be
z - z₀ = a(x-x₀) + b(y-y₀)
z - 1 = 0(x-0) + 0(y-0)
z - 1 = 0 + 0
z = 1
Therefore equation of the tangent plane is z = 1
This answer would be 21 because you’d just do 15 increased by 40% which gave me 21
Answers:
The length of XY is 4
The length of ZW is 6
Because we don't get the same length (for XY and ZW), this means that the segments are not congruent.
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To find the length of segment XY, you can count the number of spaces between -7 and -3 to get 4 units. Or you can subtract and use the absolute value notation to ensure the result is positive
|-7-(-3)| = |-7+3| = |-4| = 4
Do the same for segment ZW.
|2-8| = |-6| = 6
the opposite or addictive increase of 5x is -5x.
the opposite or addictive increase of 5x + 8 is -5x -8.
Answer:
7
Step-by-step explanation:
on edg