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3 years ago

13

The first quartile of a data set is 23, the median is 30,the third quartile is 33, and an outlier is 50. Which of these data val

ues would be represented by a point in a modified box plot?

1 answer:

Len [333]3 years ago

6 0

Answer:50

Step-by-step explanation:

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A square and a rectangle have the same area. If the dimensions of the rectangle are 4 ft by 16 ft, how long is a side of the squ

Maru [420]

9514 1404 393

Answer:

B. 8 ft

Step-by-step explanation:

The area of the rectangle is ...

A = LW = (16 ft)(4 ft) = 64 ft²

The area of the square in terms of its side length is ...

A = s²

For the square to have the area of the rectangle, its side length must be ...

64 ft² = s²

s = √(64 ft²) = 8 ft

A side of the square is 8 feet long.

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3 years ago

Emily has nickels and quarters. She has 3 fewer

lawyer [7]

Answer:

Step-by-step explanation:

she has 3 quarters

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2 years ago

Annual snowfall in Anchorage, Alaska, is normally distributed with a mean height of 76 inches and a standard deviation of 4.7 in

lukranit [14]

Answer:

67.75%

Step-by-step explanation:

Given:

Given that:

µ = 76 ; σ = 4.7

P(x < 80.7) - P(x < 71.4)

Obtain the standardized score, Z ; x = 71. 4

Zscore = (x - μ) / σ

P(x < 71.4) = (71.4 - 76) / 4.7

P(x < 71.4) = - 4.6 / 4.7

P(x < 71.4) = - 0.9787

P(z < 0.9787) = 0.16386

x = 80.7

P(x < 80.7) = (80.7 - 76) / 4.7

P(x < 80.7) = 4.7 / 4.7

P(x < 80.7) = 1

P(z < 1) = 0.84134

0.84134 - 0.16386 = 0.67748 = 67.748% = 67.75%

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2 years ago

You have just used the network planning model and found the critical path length is 30 days and the variance of the critical pat

joja [24]

Answer:

0.726 is the probability that the project will be completed in 33 days or less.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30 days

Variance = 25 days

Standard Deviation,

$\sigma = \sqrt{\text{Variance}} = \sqrt{25} = 5$

We assume that the distribution of path length is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(completed in 33 days or less)

$P( x \leq 33) = P( z \leq \displaystyle\frac{33 - 30}{5}) = P(z \leq 0.6)$

Calculation the value from standard normal z table, we have,

$P(x \leq 33) = 0.726 = 72.6\%$

0.726 is the probability that the project will be completed in 33 days or less.

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3 years ago

Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t

frozen [14]

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

$c^{2} =a^{2}+b^{2}+2abcos\alpha$ ---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and $\alpha$ is the angle between a and b .

In equation 1 , the maximum and minimum values of $cos\alpha$ are 1 and -1.

so the value of c lies in between

⇒ $\sqrt{a^{2}+b^{2}-2ab }$ and $\sqrt{a^{2}+b^{2}+2ab }$ = $|a-b| and |a+b|$

Given a=13.2 and b=6.7 so the the side lies in between |13.2-6.7| and |13.2+6.7|

so the third side lies between 6.5 and 19.9

3 0

3 years ago