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Bas_tet [7]
4 years ago
5

Simplify the expression. 3t(t - 5) + 6t to the 2nd power

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
7 0
<span>: 2s + 3t = 28, 2s = 28 - 3t s = 14 - 3t/2 Substitute s into second equation 5s + 6t = 61, 5(14 - 3t/2) + 6t = 61, 70 - 15t/2 + 6t = 61, 70 - 3t/2 = 61, 3t/2 = 9, t = 6. We can then substitute t back into first equation: 2s + 3t = 28, 2s + 3 * 6 = 28, 2s = 10, s = 5. So the final answer is: s = 5 t = 6</span>
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frozen [14]

Answer:

8 ft i think there is't much context to go off of though

Step-by-step explanation:

7 0
3 years ago
A rectagular, above ground pool is 18 feet long, 9 feet wide, and 54 inches deep. One cubic foot of water weighs about 62.4 poun
ollegr [7]

Answer:

45,489.6 pounds!

Step-by-step explanation:

To solve this problem, first we need to find the volume of the pool.

We know that the dimensions of the pool are:

Width = 9ft

Length = 18ft

Height = 54in = 4.5 ft

So the volume of the pool is:

Volume = Width x Length x Height = 9ftx18ftx4.5ft = 729ft^3

We know that one cubic foot of water weights about 62.4 pounds. To fill the  pool, we will need 729ft^3 of water.

So the weight of the water is:

Weight = 729ft^3 x 62.4 pounds/ft = 45,489.6 pounds!

4 0
3 years ago
Three spherical balls with radius r are contained in a rectangular box. two of the balls are each touching 5 sides of the rectan
olganol [36]

Answer:

The volume of the space between the balls and the rectangular box is 4r^{3}(6 - \pi)

Step-by-step explanation:

The attachment below shows the description of the rectangular bow and the three spherical balls.

From the description,  

  • Two of the balls are each touching 5 sides of the rectangular box, say the 5 sides touched by one of the balls are sides 1,2,3,4, and 5; then the other ball will touch sides 2,3,4,5, and 6).  
  • The middle ball also touches four sides of the rectangular box, These four sides touched by the middle ball will be sides 2,3,4, and 5.

This means the balls are tightly fitted into the rectangular box.

Each of the balls has a radius r

Hence, The volume of one of the balls is given by the volume of a sphere

Volume of a sphere = \frac{4}{3} \pi r^{3} \\

The volume occupied by one of the balls is \frac{4}{3} \pi r^{3} \\

∴ The volume occupied by the three spherical balls will be

3 × \frac{4}{3} \pi r^{3} \\

= 4\pi r^{3}

The volume occupied by the three spherical balls 4\pi r^{3}

For the rectangular box,

The volume of a rectangular box = l w h

Where l\\ is the length

w is the width and

h is the height

Since the balls are tightly packed,

The width of the rectangular box will be the diameter of the balls

diameter of the balls = 2r

∴ w = 2r

The height of the rectangular box will also be the diameter of the balls

∴ h = 2r

The length of the rectangular box will be 3 times the diameter of the balls

∴l = 3 × 2r = 6r

Hence,

The volume of a rectangular box = 6r × 2r × 2r

= 24r³

The volume of the space between the balls and the rectangular box is given by

Volume of the space between the balls and the rectangular box =

volume of the rectangular box -  volume occupied by the three spherical balls

Volume of the space between the balls and the rectangular box= 24r³ - 4πr³

=  24r³ - 4πr³

= 4r³(6 - π)

5 0
3 years ago
Kelsey's father was renting a vehicle. The lot had 7 sedans, 9 SUVs, 6 minivans, and 3 convertibles. How many choices does Kelse
dimulka [17.4K]
This is a counting principle problem. To find the answer you multiply the choices.
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LETTER D
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3 years ago
Help help help howl is d
dedylja [7]
The answer is 15.65.
I solve it below, to find the answer you only need to use the distance formula.

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3 years ago
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