<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Answer: 2x^2+ 9x +16+ 24x- 17/ x^2- 2x +1
Step-by-step explanation:
First, you need to move 2 to the other side. You accomplish this by adding 2 to 1. You have y>3. Since your variable is smaller than 3, draw an open circle on the 3 mark and a squiggly line left of 3.
A circle is 360°. Since you only have 3 different types of weather, if you split the ° equally, each section would have 120°. The amount of rainy days is 10/30 or exactly 1/3, so 120° are rainy days.
If you do 30 x 12, it equals 360. So that means that each day is 12°. There were 8 cloudy days, so you can do 8 x 12 = 96°
