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3 years ago

Which is greater 1/3 or 1/8

Mathematics

2 answers:

frutty [35]3 years ago

4 0

1/3 is greater because it is equal to 0.33333......
1/8 is equal to 0.125. :D

pshichka [43]3 years ago

3 0

1/3= 0.333333

1/8=0.125

So definitely 1/3 is bigger.

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The LCM of 4, 9, and 10 is _______. 36 180 40 90

Anna [14]

Answer:

180

Step-by-step explanation:

Multiples of 4:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120, 124, 128, 132, 136, 140, 144, 148, 152, 156, 160, 164, 168, 172, 176, 180, 184, 188

Multiples of 9:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, 180, 189, 198

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200

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2 years ago

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ololo11 [35]

Answer:

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Step-by-step explanation:

4 0

2 years ago

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ss7ja [257]

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2 years ago

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Josie is training for a race the ratio of the number of minutes she wants to the number of miles she wants is 2043 she plans to

guajiro [1.7K]

Answer:

Josie takes 0.93 minutes to run 2 miles.

Step-by-step explanation:

We are given the following in the question:

Ratio:

Number of minutes: Number of miles = 20:43

Josie wants to run 2 miles. We have to find the number of minutes she need to run to maintain the ration.

Let x be the number of minutes Josie run.

This can be done in the following manner:

$\dfrac{20}{43} = \dfrac{x}{2}\\\\\Rightarrow x = \dfrac{20}{43}\times 2\\\\\Rightarrow x = 0.93$

Thus, Josie takes 0.93 minutes to run 2 miles.

8 0

2 years ago

where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤

marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0

3 years ago