Option C:
Height of the smaller cone is .
Solution:
Height of the larger cone = 5
Radius of the larger cone = 7
Radius of the smaller cone =3
To find the height of the smaller cone:
If two polygons are similar, then the corresponding sides are proportional to each other.
Do cross multiplication.
⇒ 15 = 7x
Option C is the correct answer.
Height of the smaller cone is .
First, convert km/h into m/s by dividing 1618 by 3.6
using the formula
MJ
Answer:
D
Step-by-step explanation:
In the original expression = 37.4 - 54.9 = -17.5
So, we have to solve all the equations but 1 of them has to equal to -17.5
A) -54.9 + (-37.4) = -92.3
Remove parentheses
= -54.9 - 37.4
Subtract the numbers
-92.3
B) 54.9 - 37.4 = 17.5
Since 54.9 is greater than 37.4 just subtract normally
4 14
5 4. 9 < ------- Line up the decimal points like this
- 3 7. 4 <--------- Subtract the decimals
-----------------
1 7 . 5 <---------- This is the final answer to B.
C) 37.4 - (- 54.9) = 92.3
Change the sign to addition
=37.4 + 54.9
Add the numbers normally
54.9
+ 37. 4
--------------
92.3
D) 37.4 + (-54.9) = -17.5
Change the sign to subtraction
= 37.4 - 54.9
Subtract them normally (but as you can see you are subtracting a smaller number from a larger number so heres a trick that you can use switch the equation by putting the larger number in first like this....)
54.9 - 37.4 = 17.5 (REMEMBER the answer is not 17.5 because the original equation of D is reversed 37.4 - 54.9 so in this case your answer should be
- 17.5)
37.4 - 54.9 = -17.5
Your final answer is D because it matches 37.4 - 54.9.
Hope this helps!
Answer:
The speed of jet in still air is 750 miles per hour and speed of wind is 130 miles per hour.
Step-by-step explanation:
Given that:
Distance traveled by jet against the wind = 2480 miles in 4 hours
Combined speed = =
Combined speed = 620 miles per hour
Distance traveled with wind = 7040 miles in 8 hours
Combined speed =
Combined speed = 880
Let,
Speed of jet = x
Speed of wind = y
When jet travels against the wind, the speed will be subtracted
x-y=620 Eqn 1
When jet travels with the wind, the speed will be added
x+y=880 Eqn 2
Adding Eqn 1 and 2
(x-y)+(x+y)=620+880
x-y+x+y=1500
2x=1500
Dividing both sides by 2
Putting x=750 in Eqn 2
750+y=880
y=880-750
y=130
Hence,
The speed of jet in still air is 750 miles per hour and speed of wind is 130 miles per hour.
Answer:
hope this helps you with the graphs
Step-by-step explanation: