Number 12 please help please

Mathematics

1 answer:

DENIUS [597]3 years ago

8 0

Answer:

Im not 100% but I think it should be, AC and AB??

Step-by-step explanation:

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I will give BRAINLIEST PLS HELP y = x + 1/2 and z = 2x - 3, which of the following is equivalent to y + yz? PLS HELP

STALIN [3.7K]

Answer:

y+yz is: $2x^2-2x-1$

Step-by-step explanation:

Given expressions are:

$y = x+\frac{1}{2}\\z = 2x-3$

The given expressions are polynomials and we have to find the value of y+yz

First of all, we will find the product of y and z

We will use the distribution to find the product.

$yz = (x+\frac{1}{2})(2x-3)\\= x(2x-3)+\frac{1}{2}(2x-3)\\= 2x^2-3x+x-\frac{3}{2}\\=2x^2-2x- \frac{3}{2}$

The next step is to add y and yz

$y+yz = (x+\frac{1}{2})+(2x^2-3x-\frac{3}{2})\\Combining\ like\ terms\\= 2x^2+x-3x+\frac{1}{2} -\frac{3}{2}\\=2x^2-2x + \frac{1-3}{2}\\=2x^2-2x+\frac{-2}{2}\\=2x^2-2x-1$

The answer is not one of the options which i assume might be a typing mistake.

Hence,

y+yz is: $2x^2-2x-1$

6 0

3 years ago

A jewelry store has 311.75 ounces of 14-carat gold in stock.

WARRIOR [948]

Answer:

$\boxed{\text{(a) 86 necklaces; (b) \$2220}}$

Step-by-step explanation:

(a) Number of necklaces

3⁵/₈ = 3.625

$\text{No. of necklaces} = 311.75\text{ oz} \times \dfrac{\text{1 necklace}}{3.625\text{ oz}} = \textbf{ 86 necklaces}\\\\\text{You can make } \boxed{\textbf{86 necklaces}} \text{ from 311.75 oz of 14K gold}$

(b) Value of gold in each necklace

There are 3.625 oz of 14K gold in each necklace. Pure gold is 24K.

$\text{Mass of pure gold} = \text{3.625 oz} \times \dfrac{\text{14K}}{\text{24K}} = \text{2.1146 oz}$

Pure 24K gold is worth $1050/oz.

$\text{Value of pure gold} = \text{2.1146 oz} \times \dfrac{\text{\$1050}}{\text{1 oz}} = \textbf{\$2220}\\\\\text{The value of the gold in each necklace is } \boxed{\textbf{\$2220}}$