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Ierofanga [76]
3 years ago
12

What does it mean if the hundred digit of my number is less than tens digit. The ones digit is greater than the tens digit. What

could my number be?
Mathematics
1 answer:
leonid [27]3 years ago
3 0
Every number consists of digits which have their own value. If the number consists of 3 digits, then the rightmost digit is for ones, middle digit is for tens and leftmost digit is for hundreds (it goes on and on with more-than-3-digit-numbers). About your task:

Hundred digit is smaller than tens digit and tens digit is smaller than ones digit. It means that the leftmost digit is the lowest, the rightmost digit is the greatest and the middle digit is a value between both of them.

For example:

123, 258, 346, 789, 278, 568 etc. etc.


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The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
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Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

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i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

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AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

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-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

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So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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