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Ierofanga [76]
3 years ago
12

What does it mean if the hundred digit of my number is less than tens digit. The ones digit is greater than the tens digit. What

could my number be?
Mathematics
1 answer:
leonid [27]3 years ago
3 0
Every number consists of digits which have their own value. If the number consists of 3 digits, then the rightmost digit is for ones, middle digit is for tens and leftmost digit is for hundreds (it goes on and on with more-than-3-digit-numbers). About your task:

Hundred digit is smaller than tens digit and tens digit is smaller than ones digit. It means that the leftmost digit is the lowest, the rightmost digit is the greatest and the middle digit is a value between both of them.

For example:

123, 258, 346, 789, 278, 568 etc. etc.


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The difference of the present ages of two sister in 5 yrs
Gekata [30.6K]

Answer:

4 and 9

Step-by-step explanation:

let their ages be x and x - 5, then in 4 years their ages will be

x + 4 and x - 5 + 4 = x - 1 , and the product is 104, thus

(x + 4)(x - 1) = 104 ← expand factors on left using FOIL

x² + 3x - 4 = 104 ( subtract 104 from both sides )

x² + 3x - 108 = 0 ← in standard form

(x + 12)(x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 12 = 0 ⇒ x = - 12

x - 9 = 0 ⇒ x = 9

However, x > 0 ⇒ x = 9

Thus

Their present ages are 9 and 9 - 5 = 4

4 0
3 years ago
What is x – 8.1 = 5.3
Artemon [7]
Add 8.1 to both sides to find x!
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6 0
3 years ago
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Q+9/2 * 4q/q+5=?<br><br> a)2+9<br> b)2q<br> c)2/q<br> d)q/2
snow_lady [41]
Te answer would be q/2, or C. if you need further details dm me
8 0
4 years ago
Select the correct answer. What is true of the function as the x values increase?
Alinara [238K]

Answer:

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Step-by-step explanation:

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Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
Soloha48 [4]

Given :

A vector v = 10i - 24k.

To Find :

A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction  of vector v is :

\^{v}=\dfrac{v}{|v|}\\\\\^{v}=\dfrac{10i-24k}{\sqrt{10^2+24^2}}\\\\\^{v}=\dfrac{10i-24k}{26}

Now , vector of magnitude 3 in direction v is :

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