First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
Step-by-step explanation:
3
Answer:
Weakest value = 0.0196
Strongest value = 0.5929
Step-by-step explanation:
Given:
Choices
0.691
-0.14
-0.24
-0.77
Computation:
0.691² = 0.477481
-0.14² = 0.0196
-0.24² = 0.0576
-0.77² = 0.5929
Weakest value = 0.0196
Strongest value = 0.5929
B. The sun is lighting up different amounts of the moon
