Answer:
Step-by-step explanation:
=x^2-x+3+3x^2-3x+2
=5x^2-4x+5
If the game will start at 11:00 A.M., but the players must arrive at the field three-quarters of an hour early to warm up, it refers to 8:45 a.m. Why? If we start to count in 11 backward and start to trace the three-quarters, it shows that 10:45, 9:45, and 8:45 are the three-quarters. So Hamid statement that he has to be at the field at 9:45 A.M is not correct.
Distribute first
a(b+c)=ab+ac
7y(8y-7)=56y^2-49y
now we have
56y^2-49y+46y
56y^2-3y
tada
If you have a calculator, you can use the inverse cos " cos⁻¹ " key. Many upper level books write that as Arccos so as not to confuse you with a negative exponent. We do that because if you take the cosine of any angle, and then the inverse cosine of any angle, it leads you back to the original angle. Think of it as a big "UNDO" button.
To one decimal place, that result is 61.6 degrees.
We basically have to cancel values on both sides until they are both on common ground.
7 + 3x = 5x + 13
-7 from both sides...
3x = 5x + 6
-5x from both sides...
-2x = 6
/-2 from both sides...
x = -3
Hope this helps!
