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kobusy [5.1K]
3 years ago
11

The dimensions of the base of Box 1 are x by 3x. The base area of Box 1 is: 3x 3x2 3x3 4x

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

The answer to the 1st question "The base area of Box 1 is..."

<h2>B.   3x2</h2>

The answer to the 2nd question, "The dimensions of the base of Box 2 are x by 4x − 1." is..

<h2>A.   4x2 – x</h2>

Step-by-step explanation:

Lunna [17]3 years ago
4 0
<h3>The base area of box 1 is 3x^2\ square\ units</h3>

<em><u>Solution:</u></em>

Given that,

The dimensions of the base of Box 1 are x by 3x

Length = x

Width = 3x

To find: base area of box 1

<em><u>The base area is given as:</u></em>

base\ area = length \times width\\\\base\ area = x \times 3x\\\\base\ area = 3x^2

Thus base area of box 1 is 3x^2\ square\ units

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If the length of a flag is 18 inches and the width is 12 inches what is the area
attashe74 [19]

Answer:

18 by 12 is 216

8 0
3 years ago
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An open-top rectangular box with square base is to be made from 100 square feet of material, as shown.
-Dominant- [34]

The largest possible volume of the given box is; 96.28 ft³

<h3>How to maximize volume of a box?</h3>

Let b be the length and the width of the base (length and width are the same since the base is square).

Let h be the height of the box.

The surface area of the box is;

S = b² + 4bh

We are given S = 100 ft². Thus;

b² + 4bh = 100

h = (100 - b²)/4b

Volume of the box in terms of b will be;

V(b) = b²h = b² * (100 - b²)/4b

V(b) = 25b - b³/4

The volume is maximum when dV/db = 0. Thus;

dV/db = 25 - 3b²/4

25 - 3b²/4 = 0

√(100/3) = b

b = 5.77 ft

Thus;

h = (100 - (√(100/3)²)/4(5.77)

h = 2.8885 ft

Thus;

Largest volume = [√(100/3)]² * 2.8885

Largest Volume = 96.28 ft³

Read more about Maximizing Volume at; brainly.com/question/1869299

#SPJ1

4 0
1 year ago
Don't know this please help me give brainly
Sergio039 [100]
Just pick random it’s helpful
6 0
3 years ago
7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t
Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

\frac{x^a}{x^b}=x^{a-b}

x^0=1

(x^a)(x^b)=x^{a+b}

x^{-a}=\frac{1}{x^a}


\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=

\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=

\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=

(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=

(7^{-5-(-5)})(2^{0-3})=

(7^0)(2^{-3})=

\frac{1}{2^3}=

\frac{1}{8}

7 0
3 years ago
The store buys a vase for $25. The vase sells for $55. What is the markup on the vase?
Hatshy [7]

Answer:

The answer is $30

Step-by-step explanation:

Markup refers to the amount added to the cost price of goods to cover overhead and profit.

The vase was bought for $25, then is now selling for $55

$55-$25=$30

hope this helps please mark brainliest :)

4 0
2 years ago
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