<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
11 minutes has passed just subtract
Answer:
10x - 5 / 4
Step-by-step explanation:
15 - ( -10x ) - 20 / ( 12 + ( -8 ) )
= ( -5 ) + 10x / ( 4 )
= 10x - 5 / 4
<em>Hope it helps</em>
<em>:D</em>
Answer:
1. 320 2. 580
Step-by-step explanation:
when you round 320, it is 320 because the hundredths place is 0, which is under 5 so the numbers wouldn't change.
When you round 579, the hundredths place is a 9, which is over 5 so you add 1 to seven to get 8.
