What is the value of x squared =169

Mathematics

1 answer:

Rufina [12.5K]2 years ago

3 0

$x^{2} =169\\ \\ x^{2}=13^2\ \ \ \Leftrightarrow\ \ \ x=13\ \ \ or\ \ \ x=-13$

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Find the equation of the line that passes through the following two points: (3, -7) and (7, 2)

Wittaler [7]

Answer:

$y=\frac{9}{4}x-\frac{55}{4}$

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: $\frac{y2-y1}{x2-x1}$

Given points: (3, -7), (7, 2)

(3, -7) = (x1, y1)

(7, 2) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

$\frac{2-(-7)}{7-3}$

Simplify:

2 - (-7) = 2 + 7 = 9

7 - 3 = 4

$\frac{9}{4}$

The slope is $\frac{9}{4}$ .

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

$2=\frac{9}{4}(7)+b$

$2=\frac{63}{4}+b$

$-\frac{55}{4} =b$

The y-intercept is $-\frac{55}{4}$ .

Now that we know the slope and the y-intercept, we can write the equation:

$y=\frac{9}{4}x-\frac{55}{4}$

6 0

2 years ago

HELP PLEASE,<br><br> Part a of the question was posted earlier on.

Elanso [62]

$\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7
\\\\\\
\lim\limits_{x\to 6}~(6)+7=13
\\\\\\
\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\
\textit{the same limit as }x+7$