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3 years ago

Calculate the oxidation number of the iodine (I) in each compound: HIO4 = I2 = NaI = HIO3 =

Chemistry

2 answers:

Oduvanchick [21]3 years ago

8 0

Answer:

the answer has the plus sign in it...

-1

Alisiya [41]3 years ago

3 0

1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.

2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.

3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.

4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.

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Kc for the reaction of hydrogen and iodine to produce hydrogen iodide, H2(g) I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Determine the init

Jlenok [28]

Answer : The initial concentration of HI and concentration of $HI$ at equilibrium is, 0.27 M and 0.386 M respectively.

Solution : Given,

Initial concentration of $H_2$ and $I_2$ = 0.11 M

Concentration of $H_2$ and $I_2$ at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

Initially 0.11 0.11 C

At equilibrium (0.11-x) (0.11-x) (C+2x)

As we are given that:

Concentration of $H_2$ and $I_2$ at equilibrium = 0.052 M = (0.11-x)

0.11 - x = 0.052

x = 0.11 - 0.052

x = 0.058 M

The expression of $K_c$ will be,

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}$

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of $HI$ at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0

3 years ago

Why is chemical energy stored energy?

Mashutka [201]

Because chemical energy is stored the chemical reaction takes place the stored chemical energy is released.

5 0

3 years ago

Which chemical equations show an oxidation-reduction reaction? O2 + 2H2 → 2H2O MgSO4 + CaCl2 → MgCl2 + CaSO4 2Al + 6HI → 2AlI3 +

wolverine [178]

Answer:- $O_2+2H_2\rightarrow 2H_2O$ and $2Al+6HI\rightarrow 2All_3+3H_2$

Explanations:- In the first equation, the oxidation number of O is decreasing from 0 to -2 where as the oxidation number of H is increasing from 0 to +1. As the oxidation number is increasing for one element(H) and decreasing for other element(O), it is an oxidation-reduction reaction.

Second reaction is a double displacement reaction so there is no change to the oxidation numbers of the elements and hence it is not oxidation-reduction reaction.

In third reaction, the oxidation number of Al is increasing from 0 to +3 and the oxidation number of H is decreasing from +1 to 0. Here again there is an increase and decrease to the oxidation numbers of two elements, it is oxidation-reduction reaction.

fourth and fifth reactions are again double displacement reactions and so there is no change to oxidation numbers for any of the elements and they are not the oxidation-reduction reactions.

So, the only correct equations are $O_2+2H_2\rightarrow 2H_2O$ and $2Al+6HI\rightarrow 2All_3+3H_2$ .

6 0

3 years ago

What is a destructive force caused by the convection in the mantle

Karolina [17]

Answer:

convergent margins.

Explanation:

Mantle convection causes the phenomenon of plate tectonics on the earth surface.

From plate tectonics, we understand that the earth surface is broken into several giant slabs made up of the crust and upper part of the mantle. This is called the lithosphere. The lithosphere sits on the weak and plastic asthenosphere in the mantle.

The mantle is made up of series of convective cells through which hot, molten and lighter materials which are more buoyant rises up. They are then replaced by cold and denser materials. This system of exchange sets up a convection system which drives the overriding lithospheric plates.

The plates can collide with one another at convergent margins, some can move away from one another at divergent margins and some just slides past one another at transform margins.

A convergent margin is a destructive margin in which the lithosphere is destroyed either by collision or subduction.

8 0

4 years ago

Read 2 more answers

Which pair of substances cannot form a buffered aqueous solution?

Iteru [2.4K]

D. HNO3 and NaNO3; Pair of substances cannot form a buffered aqueous solution is hno3 and nano3.

More about HNO3 and NaNO3:

The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples may have a yellow hue from breakdown into nitrogen oxides.

The majority of nitric acid that is sold commercially has a 68% concentration in water. Nitric acid that is flaring when the solution contains more than 86% HNO3.

The chemical with the formula NaNO 3 is sodium nitrate. To distinguish it from regular saltpetre, potassium nitrate, this alkali metal nitrate salt is sometimes known as Chile saltpetre Nitratine, nitratite, are other names.

Learn more about HNO3 here:

brainly.com/question/6944420

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5 0

2 years ago