Answer:
The rate of disappearance of 
for this period is
Explanation:
Initial concentration of = x = 0.0138 M
Final concentration of = y = 0.00886 M
Time elapsed during change in concentration = Δt = 374 s
Change in concentration ,![\Delta [NO_2]](https://tex.z-dn.net/?f=%5CDelta%20%5BNO_2%5D)
= y - x = 0.00886 - 0.0138 M = -0.00494 M
The rate of disappearance of for this period is:
![\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BNO_2%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B-0.00494%20M%7D%7B374%20s%7D%3D-1.32%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
3KOH + H₃PO₄ ----> K₃PO₄ + 3H₂O
3 moles 1 mole
3 moles KOH ------ 1 mole H₃PO₄
X moles KOH ------ 1,56 mol
X = 3×1,56
X = 4,68 moles of KOH
:)
<span>Like if it didn't boil, nothing evaporated, didn't even get warm. You just have to think about it. </span>
In a reduction-oxidation or better known as REDOX reaction, the substance that reduces the oxidation state is known as the substance that is REDUCED. It serves as the oxidizing agent. Thus, Au3+ in this number is considered as the oxidizing agent.
Answer:
a, ocean water evaporating
