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ryzh [129]
2 years ago
11

Which pair of substances cannot form a buffered aqueous solution?

Chemistry
1 answer:
Iteru [2.4K]2 years ago
5 0

D. HNO3 and NaNO3; Pair of substances cannot form a buffered aqueous solution is hno3 and nano3.

More about HNO3 and NaNO3:

The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples may have a yellow hue from breakdown into nitrogen oxides.

The majority of nitric acid that is sold commercially has a 68% concentration in water. Nitric acid that is flaring when the solution contains more than 86% HNO3.

The chemical with the formula NaNO 3 is sodium nitrate. To distinguish it from regular saltpetre, potassium nitrate, this alkali metal nitrate salt is sometimes known as Chile saltpetre  Nitratine, nitratite, are other names.

Learn more about HNO3 here:

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For which solutes dissolved in a liquid is the overall enthalpy of solution exothermic? A-some gases and most solids B- some sol
lina2011 [118]

Answer:

B

Explanation:

Just took the test

8 0
3 years ago
Read 2 more answers
Jeffrey is on his skateboard and starts skating down a ramp. Ten seconds later he is travelling at
AfilCa [17]

Answer: 2m/s^2

Explanation:

Velocity of skateboard = 20.0 m/s.

Time taken = Ten seconds (10 s)

Acceleration ​= ?

Recall that acceleration is the change in velocity of a body per unit time.

i.e Acceleration = (velocity / Time)

Acceleration = 20.0m/s ➗ 10 s

Acceleration = 2m/s^2

Thus, Jeffrey acceleration was 2m/s^2

7 0
3 years ago
On the basis of electronegativity, which of these pairs of elements is most likely to form monatomic ions?
mixer [17]

Answer is: Cl and Na.

sodium and chlorine are in third period and they have very different properties. Sodium is solid metal and chlorine is gaseous nonmetal.

They form compound NaCl (Sodium chloride), because sodium lost one valence electron and form cation Na⁺, chlorine gain one electron and form anion Cl⁻.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.

Other examples are metal-metal pairs and they do not form cation and anion.

8 0
3 years ago
Read 2 more answers
Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi
JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

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4 0
2 years ago
A 367.8 g sample of potassium chlorate was decomposed according to the following equation:
Pie
The answer is A i did this before hope this helps
7 0
3 years ago
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