Answer:
350.64g
Explanation:
So first you must know that M is mol/L
Next solve the problem using dimensional analysis
2L NaCl (3 mol/L) = 6 mol NaCl
After you got the number of moles you should look at your periodic table to find the molar mass
I see that it's 58.44g/mol
Use dimensional analysis again!
6 mol (58.44g/mol) = 350.64g
Don't forget to make me brainliest!
Answer: (a) The solubility of CuCl in pure water is 
.
(b) The solubility of CuCl in 0.1 M NaCl is 
.
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.
Initial: 0 0
Change: +x +x
Equilibm: x x
And, equilibrium expression is as follows.
![K_{sp} = [Cu^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCu%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
x =
Hence, the solubility of CuCl in pure water is .
(b) When NaCl is 0.1 M,
,
, 
Net equation: 
= 0.1044
So for,
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' = 
0.1044 = 
x =
Therefore, the solubility of CuCl in 0.1 M NaCl is .
Answer: The answer to this question is transpiration.
Explanation: I know this answer because i looked it up in a book. The other explanation is I study about this a lot.
Answer:
<h2>1.16 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>1.16 moles</h3>
Hope this helps you
Answer: Option (b) is the correct answer.
Explanation:
Porosity means the ease with which a fluid can pass through between a rock or cracks etc.
If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.
If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.
Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.
If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.
Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.
