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frozen [14]
3 years ago
14

Write an inequality for x that would give this rectangle a perimeter of at least 300ft

Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

The inequality for x is:

x\geq 142

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = (x+5) ft

Perimeter is at least 300 ft

To write an inequality for x.

Solution:

Perimeter of a rectangle is given as:

⇒ 2l+2w

where l represents length of the rectangle and w represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ 2(x+5)+2(3)

Using distribution:

⇒ 2x+10+6

Simplifying.

⇒ 2x+16

The perimeter is at lest 300 ft. So, the inequality can be given as:

⇒ 2x+16\geq 300

Solving for x

Subtracting both sides by 16.

⇒ 2x+16-16\geq 300-16

⇒ 2x\geq284

Dividing both sides by 2.

⇒ \frac{2x}{2}\geq \frac{284}{2}

⇒ x\geq 142   (Answer)

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Answer:

91.8 feet^3

Step-by-step explanation:

We can find out the area of a circle and then multiple that by the height to get the volume of the tree trunk (which is a cylinder).

Area of circle formula: pi x r^2

3.14 x 1.5^2 = 7.065

Now we can multiple it by the height and round to the nearest 10th.

7.065 x 13 = 91.845

91.845 -> 91.8

Hope this helps! Brainliest?

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Printer A prints for 10 minutes, so prints

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... (40 pages/minute)×(7 minutes) = 280 pages


At the end of 10 minutes, the two printers will have printed

... 300 pages + 280 pages = 580 pages

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If I get paid $8.00 per hour and I also get paid time-and-a-half for overtime hours, how much would I get paid for each overtime
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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviat
nexus9112 [7]

Answer:

Two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

Step-by-step explanation:

We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviation of 0.07 millimeters.

<em>Let X = diameters of bolts produced in a machine shop</em>

So, X ~ N(\mu=5.65,\sigma^{2} = 0.07^{2})

The z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

<u>Now, we have to find the two diameters that separate the top 4% and the bottom 4%.</u>

  • Firstly, Probability that the diameter separate the top 4% is given by;

        P(X > x) = 0.04

        P( \frac{X-\mu}{\sigma} > \frac{x-5.65}{0.07} ) = 0.04

        P(Z > \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the top 4% is given as 1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = 1.7507

              x-5.65 = 0.07 \times 1.7507

                         x = 5.65 + 0.122549 = 5.77

  • Secondly, Probability that the diameter separate the bottom 4% is given by;

        P(X < x) = 0.04

        P( \frac{X-\mu}{\sigma} < \frac{x-5.65}{0.07} ) = 0.04

        P(Z < \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the bottom 4% is given as -1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = -1.7507

              x-5.65 = 0.07 \times (-1.7507)

                         x = 5.65 - 0.122549 = 5.53

Therefore, the two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

4 0
3 years ago
The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r
vichka [17]

Answer:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

\hat p=0.77 estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:  

Null hypothesis:p\leq 0.75  

Alternative hypothesis:p > 0.75  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

4 0
3 years ago
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