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frozen [14]
3 years ago
14

Write an inequality for x that would give this rectangle a perimeter of at least 300ft

Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

The inequality for x is:

x\geq 142

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = (x+5) ft

Perimeter is at least 300 ft

To write an inequality for x.

Solution:

Perimeter of a rectangle is given as:

⇒ 2l+2w

where l represents length of the rectangle and w represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ 2(x+5)+2(3)

Using distribution:

⇒ 2x+10+6

Simplifying.

⇒ 2x+16

The perimeter is at lest 300 ft. So, the inequality can be given as:

⇒ 2x+16\geq 300

Solving for x

Subtracting both sides by 16.

⇒ 2x+16-16\geq 300-16

⇒ 2x\geq284

Dividing both sides by 2.

⇒ \frac{2x}{2}\geq \frac{284}{2}

⇒ x\geq 142   (Answer)

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GIVEN:MN is an angle bisector of ∠JMK<br> Prove:m∠JMN=1/2m∠JMK
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                  Statements                                           Reasons

1. MN is an angle bisector of ∠JMK        1. Given

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7 0
3 years ago
What is the answer to the question
algol13
The angles given are opposite each other and are known as "vertical angles." Vertical Angles are congruent meaning that they have the same measure. So, we can just set the two expressions equal to each other and solve for x, like this:
4x+50=150

Subtract 50:
4x=100

Divide by 4:
x =  \frac{100}{4} = 25

Thus, x = 25°.

5 0
3 years ago
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