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Korvikt [17]
2 years ago
12

BRILLIANT Q

Mathematics
1 answer:
Sholpan [36]2 years ago
7 0

Answer:

The problem is all about volumes.

The volume of a hemisphere is defined as

V=\frac{2}{3} \pi r^{3}

According to the problem

d_{outside}=44.6cm

d_{inside}=41.6cm

Using the definition of radius

r_{outside}=\frac{44.6cm}{2}=22.3cm

r_{inside}=\frac{41.6cm}{2}=20.8cm

Now, the volume of the inside bowl is

V_{inside}=\frac{2}{3}\pi(20.8cm) ^{3} \approx 5999.27 (3.14) \ cm^{3} \approx 18837.71 \ cm^{3}

Therefore, the bowl can have 18,837.71 cubic centimeters of soup. (A)

The volume of the clay needed can be found with the differnece between hemispheres.

V_{clay}=V_{outside}  -V_{outside}

V_{clay}=\frac{2}{3}(3.14)(22.3cm)^{3}-18837.71cm^{3}=    23214.16 cm^{3}-18837.71cm^{3}=  4376.45 \ cm^{3}

Therefore, we needed 4376.45 cubic centimeters of clay to make a single bowl. (B)

At last, the space that a single bowl occupies in the box is

V_{outside}=23214.16 \ cm^{3}

If we have 6 bowls, the total volume is

V_{total}=6(23214.16 \ cm^{3} )= 139284.96 \ cm^{3}

Now, we need to find the volume of the box

V_{box}=22.5cm \times 90cm \times 135 cm =  273375cm^{3}

The empty space between the box and the 6 bowls is

V_{sawdust}=V_{box} - V_{total}=273375 cm^{3}-139284.96 cm^{3} =134090.04cm^{3}

This empty space volume represents the sawdust packing needed, because the function of it is to fill the empty space.

Therefore, we need 134090.04 cubic centimeters of sawdust packing. (C)

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Answer:

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Number of calls received in 2nd evening = 33

Number of calls received in 3rd evening = 72

Step-by-step explanation:

Let

number of calls received in first evening be "x"

number of calls received in 2nd evening be "y"

number of calls received in 3rd evening be "z"

Total, in 3 evenings, we have 129 phone calls, so we can write:

x + y + z = 129

3rd evening, 3 times as first evening. We can write:

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