Why do you think the two empires did not last very long?

RoseWind [281]

G(x) = 1 - 2x²

The domain: x ∈ R /all real numbers/

3 0

4 years ago

Suppose an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that

MissTica

Answer:

4.07

Step-by-step explanation:

The sample size is 12. The number of treatments is 4. Thus, the degrees of freedom associated with the sum of square error is 8 which is sample size minus number of treatments. The degree of freedom is 3 which is number of treatments minus 1. The theoretical F value is determined by entering the F table (pp.723-24) at 3 degrees of freedom for the numerator and 8 degrees of freedom for the denominator for the level of significance given which in this case is 0.05.

4 0

3 years ago

A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa

UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so $\mu = \frac{14}{60} = 0.2333$

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081$

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0

4 years ago

Susan is trying to decide between two jobs. One job pays $12 per hour for the first 36 hours and $15 per hour for any additional

nasty-shy [4]

Answer:

For the first question (For which job will she earn more if she works 40 hours a week), the answer is the second job.

For the second question (How much more per year will this be if she works 50 weeks per year), the answer is 25$ extra a year.

First i multiplied $12 times 36.

$12 x 36 = $432

Then i multiplied $15 times 4.

$15 x 4 = $60

Now add those together

$432 + $60 = $492

That's how much she would make in a week for the first job, if she worked 40 hours a week.

For the second job, i did the exact same process.

$11.50 x 35 = $402.5

$18 x 5 = $90

$402.5 + $90 = $492.5

She would get 50 more cents a week, if she worked 40 hours a week.

For the second question, i multiplied the first job total by 50, since she is working 50 weeks a year.

$492 x 50 = $24,600

Thats her total of a year, for the first job.

Do this with the second job.

$492.5 x 50 = $24,625

As you can see, she would get $25 more in the second job, than the first job.

I hope this helped!

7 0

3 years ago

Tim must read 2 books from a list of 7 recommended books for his summer reading program. In how many different ways can Tim choo

Marianna [84]

There are 21 ways Tim choose 2 books from the 7 recommended book

Solution:

Given that Tim must read 2 books from a list of 7 recommended books for his summer reading program

To find: different ways can Tim choose 2 books from the 7 recommended books

This is a combination problem

A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected

The formula for combinations is:

$n C_{r}=\frac{n !}{r !(n-r) !}$

where n represents the number of items, and r represents the number of items being chosen at a time

Here we have to choose 2 books from 7 books

Therefore, n = 7 and r = 2

Substituting values in above formula, we get

$\begin{aligned}&7 C_{2}=\frac{7 !}{2 !(7-2) !}\\\\&7 C_{2}=\frac{7 !}{2 ! \times 5 !}\end{aligned}$

For a number n, the factorial of n can be written as,

$n !=n \times(n-1) \times(n-2) \dots \dots \times 2 \times 1$

Therefore, we get

$7 C_{2}=\frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1 \times 5 \times 4 \times 3 \times 2 \times 1}\\\\7C_2 = 7 \times 3 = 21$

Thus there are 21 ways Tim choose 2 books from the 7 recommended book

7 0

3 years ago

Why do you think the two empires did not last very long?​

Why do you think the two empires did not last very long?