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lesya [120]
3 years ago
5

Helen is 8 years older than Jane. Twenty years ago Helen was three times as old as Jane. How old is each now? If Jane's current

age is x, what would the equation look like?
Mathematics
1 answer:
Leokris [45]3 years ago
3 0
For this case, the first thing we must do is define variables:
 x: Jane's age
 y: Helen's age
 By writing the system of equations we have:
 y = x + 8
 y-20 = 3 (x-20)
 Solving the system we have:
 x = 24
 y = 32
 Answer:
 
Jane is 24 years old
 
Helen is 32 years old
 the equation for Jane would look like:
 x + 8 = 3 (x-20) + 20
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Part A
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An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:

i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles

ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles

iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.

In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.

So that;

The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.

This implies that:

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The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.

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(2y + 3) = ( 2(1.5) + 3)

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The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.

And,

5y = 5(1.5)

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The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

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