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frez [133]
3 years ago
7

Three contractors (call them a, b, and

Business
1 answer:
patriot [66]3 years ago
4 0

Answer:  The probabilities of winning a contract are

P(A) = \frac{28}{36}  

P(B) = \frac{7}{36}  

P(C) = \frac{1}{36}


Let the Probability of C winning the contract - P(C) be 'X'

Then,

Probability of B winning the contract - P(B) will be '7X'     and

Probability of A winning the contract - P(A) will be \mathbf{P(A) = 4 * P(B) = 4*7X = 28X}

Since the total of all the probabilities is 1,

\mathbf{P(A) + P(B) + P(C) =1}

\mathbf{28X + 7X + X =1}

\mathbf{36X =1}

\mathbf{X =\frac{1}{36}}

So,

P(A) = \frac{28}{36}

P(B) = \frac{7}{36}

P(C) = \frac{1}{36}

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Missing word<em> "and the cost of one point at the time of closing"</em>

<em />

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