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Genrish500 [490]
3 years ago
14

How many ounces are in a pounds

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
16 ounces are in a pound.
DaniilM [7]3 years ago
3 0
16 Ounce. 

Hope this helped.
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Can someone help me out with this
katen-ka-za [31]

Answer:

AB=4.41

Step-by-step explanation:

Use the cosine ratio, cosine=\frac{adjacent}{hypotenuse} . Insert the values:

cos25=\frac{4}{x}

Isolate x. Multiply both sides by x:

x*(cos25)=x*(\frac{4}{x})\\\\x*cos25=4

Divide both sides by cos 25:

\frac{x*cos25}{cos25}=\frac{4}{cos25}\\\\x=\frac{4}{cos25}

Insert into a calculator:

x=4.414

Round to the nearest hundredth:

x=4.41

Done.

5 0
3 years ago
Which number is prime? <br> A. 21 <br> B. 23<br> C. 25<br> D. 27
IceJOKER [234]
B. 23


Hope this helps!!!!!!
5 0
3 years ago
Read 2 more answers
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
The value of n is both 5 times as much as the value of m and 36 more than the value of m. What are the values of n and m? Explai
tia_tia [17]
N = 5m
n = m + 36

since n is equal to both the expression in m we can say:-

5m = m + 36
4m=36

m = 9 

and n = 5*9 = 45

3 0
3 years ago
If the test for a disease is accurate 45% of the time, how often will it come back negative if a patient has the disease?
ioda
About 55% of the time
8 0
3 years ago
Read 2 more answers
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