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Goryan [66]
3 years ago
6

Please help me asap!!

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

C) 5; ASA

A <C = <E

S CB = BE

A <B = <B

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The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 19
alexgriva [62]

Answer:

p(t) = 0.19e0.10t

=>p'(t) = 0.19e0.10t (0.10*1)

=>p'(t) = 0.019e0.10t

t = 0 represents 1994

for 2002, t=2002-1994 =8

in 2002

average price =p(8)

=>average price = 0.19e0.10*8

=>average price =0.422853... million

rate of increase =p'(8)

=>rate of increase = 0.019e0.10*8

=>rate of increase =0.0422853... million per year

p(8)=$ 0.42 million

p'(8)=$ 0.042 million per year

4 0
2 years ago
Ahmad rented a truck for one day. There was a base fee of $17.99, and there was an additional charge of 88 cents for each mile d
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266 miles

Step-by-step explanation:

(244.09-17.99)/0.85=266

6 0
3 years ago
Math help What are the solutions​
Westkost [7]

Answer:

x² - 4x + 12

Step-by-step explanation:

x=2+2.82843i

x=2−2.82843i

6 0
2 years ago
Help me with this please
expeople1 [14]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base
suter [353]

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of <em>m</em> and <em>n</em> is:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

Exponent rule of division:

a^{x}\div a^{y}=a^{x-y}

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}

             =\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}

Thus, the correct option is option (3) 4 ÷ 25.

8 0
3 years ago
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