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snow_tiger [21]
3 years ago
6

Soulutions for 20-4u

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
3 0

The question seems incomplete

stiks02 [169]3 years ago
3 0

Answer:

u = 5

Step-by-step explanation:

20-4u = 0

4u = 20

u = 5

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The perimeter of the rectangle below is 166 units. Find the length of side RS.
Wittaler [7]

The length of RS is 45 units if the perimeter of the rectangle below is 166 units.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

The question is incomplete.

The complete question is:

The perimeter of the rectangle below is 166 units. Find the length of the side RS. Write your answer without variables.

The figure is in the picture please refer to the picture.

The perimeter of the rectangle = 166 units

2(4x + 2 + 5x) = 166

9x + 2 = 83

9x = 81

x = 9

The length of RS = 5x = 5(9) = 45 units

Thus, the length of RS is 45 units if the perimeter of the rectangle below is 166 units

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creativ13 [48]

The mean exists at 3 and the standard deviation exists 0.87.

Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

$\mu_{X}=3, \sigma_{X}=0.87

<h3>What is the binomial probability distribution?</h3>

The expected value of the binomial distribution exists:

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The standard deviation of the binomial distribution exists:

$\sigma_{X}=\sqrt{n p(1-p)}$$

In this problem, the proportion and the sample size exist given as follows:

p = 0.75

n = 4

Therefore, the mean and the standard deviation exist given by:

$&\mu_{X}=n p=4(0.75)=3 \\

$&\sigma_{X}=\sqrt{n p(1-p)}

$=\sqrt{4(0.75)(0.25)}=0.87

The mean exists at 3 and the standard deviation exists 0.87.

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