Answer:
If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.
Step-by-step explanation:
You have to distribute!
6(x) = 6x and 6(-6)=-36
So now you have 6x-36=-3(-x+3)
Now do the same on the other side.
-3(-x)=3x -3(3)=-9
So now, 6x-36=3x-9
Combine the like terms:
Subtract 3x in both sides.
6x-3x=3x
Now: 3x-36=-9
Add 36 in both sides.
3x=27
Divide by 3 on both sides to get x alone.
3x/3= x 27/3=9
X=9
Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.
<h3>What is the equation of a circle?</h3>
The equation of a circle of center 
and radius r is given by:
In this problem, the circle is centered at the origin, hence 
.
The circle contains the point (-13,0), hence the radius is found as follows:
Hence the equation is:
Then, we test if point (√5, 12) is on the circle:
25 + 144 = 169
Which is an identity, hence point (√5, 12) is on the circle.
More can be learned about the equation of a circle at brainly.com/question/24307696
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Answer:
D. 4x + 32; E. 4(x + 8)
Step-by-step explanation:
The correct answer is none. This problem is incorrect. The perimeter of a polygon is the sum of the lengths of all the sides. A perimeter is a length, not an area. A perimeter is expressed in feet, not square feet.
Ignoring the "square feet" part, once again, the perimeter is the sum of the lengths of all sides. Since this is a square, all sides have the same length, and there are 4 sides.
perimeter = 4s
perimeter = 4(x + 8) = 4x + 32
