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padilas [110]
3 years ago
13

If i sale 120 tickets at $25 each how much money will be made

Mathematics
2 answers:
dedylja [7]3 years ago
8 0
120tickets*25$=3000$
PSYCHO15rus [73]3 years ago
3 0
You will get 3000$ of money
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Is the fraction 12/98 a perfect square??​
quester [9]

Answer:

No

Step-by-step explanation: By dividing 12/98 you would get a decimal(0.12244897959) by this not being a whole number it can not be a perfect square.

6 0
3 years ago
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Write the number in two forms 15409
Salsk061 [2.6K]
Since 15409-1=15408 and 15408+1=15409, we can write that as one. With 15409-2, we can write the same thing with 15407+2
6 0
3 years ago
I will make the right answer the brainliest, no lie.
grigory [225]

Answer: The segment EF of the isoceles triangle ΔEFP is 10 units


Solution

If point P is equidistant from the vertices of ΔDEF, the segment PE must measure the same that the segment PF, then these two segments are congruent:

PE=PF

Then ΔEFP is an isisceles triangle, because it has two congruent sides (PE=PF), and the height of the side EF (PJ perpendicular to EF) divides ΔEFP into two congruent right triangles (ΔEJP and ΔFJP). The legs EJ and FJ must be congruent:

FJ=EJ

3x-1=x+3

Solving for x: Subtracting x and adding 1 both sides of the equation:

3x-1-x+1=x+3-x+1

2x=4

Dividing both sides of the equation by 2:

2x/2=4/2

x=2

Then:

FJ=3x-1→FJ=3(2)-1→FJ=6-1→FJ=5

EJ=x+3→EJ=2+3→EJ=5

EF=EJ+FJ→EF=5+5→EF=10

7 0
3 years ago
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Factor the common factor out of -56x4 + 16x2 + 16x
evablogger [386]

Answer:

The common factor is 8x or -8x ( I forgot if the first number needs to positive or not.

Step-by-step explanation:

-8x(7x^3-2x-2)

or

8x(-7x^3+2x+2)

Hope this is what you are looking for?

5 0
3 years ago
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Algebraically, find all remaining zeros of f(x) = 8x^3 - 6x^2-36x +27 in simplest form.
viva [34]

Answer:

x=-\frac{3\sqrt{2}}{2},\frac{3}{4},\frac{3\sqrt{2} }{2}

Step-by-step explanation:

Given expression is,

f(x) = 8x³ - 6x² - 36x + 27

For zeros of the function,

f(x) = 0

8x³ - 6x² - 36x + 27 = 0

2x²(4x - 3) - 9(4x - 3) = 0

(2x² - 9)(4x - 3) = 0

(2x² - 9) = 0

x² = \frac{9}{2}

x = \pm\frac{3}{\sqrt{2}}

x = \pm \frac{3\sqrt{2}}{2}

Or (4x - 3) = 0

x = \frac{3}{4}

Therefore, all zeros of the given functions are  x=-\frac{3\sqrt{2}}{2},\frac{3}{4},\frac{3\sqrt{2} }{2}.

7 0
3 years ago
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