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svlad2 [7]
3 years ago
7

A rectangle's length is 3 cm more than twice its width. If the perimeter is 48 cm, what is the

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

119 square centimeters.

Step-by-step explanation:

Write the problem as an equation.

2(2x+3)+2x=48

Where x is width of the rectangle. 2x+3 represents the length.

4x+6+2x=48

6x+6=48

6x=42

x=7

The width is 7 cm.   Then, find the length.

(2x+3)     Given

(2)(7)+3   Plug in 7 for x

14+3

17

Then, find the area, width*length

17*7=119

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<h3>What is rectangle?</h3>

A rectangle exists as a quadrilateral with opposite sides parallel and equivalent to each other. Also, all the angles of the rectangle exist equivalent to 90°.

As it exists given that the cylindrical container has three tennis balls that exists 5.4 inches in diameter which exist lying on its side and passes through an x-ray scanner that scans from the top only.

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