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Shtirlitz [24]
3 years ago
9

A gourment shop wants to mix coffe beans that cost $3.00 per pound with coffe beans that cost $4.25 per pound to create 25 pound

s of a new blend that cost $3.50 per pound. Find the number of pounds of each nerded to produce the new blend
Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0
If the gourmet shopkeeper mix 15 pounds of coffee beans which costs 3.0$ per pound with 10 pounds of coffee beans costing 4.25$ per pound.
The mixture of 25 pounds will cost 3.5$ per pound.

It can be found using 
3*x + 4.25*(25 -x) = 25*3.50

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Every morning, Lillian collects eggs from the hens on her family's farm. She puts the eggs in cartons of 16. On Monday, Lillian
Mars2501 [29]
Answer- D)11
37÷16=2 r5
16-5=11

5 0
3 years ago
Please help me I have been stuck on this question for ages
Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is P(g)=\frac{4}{9}

and P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}

Thus \frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}

\frac{g}{g+r}=\frac{4}{9}

\Rightarrow 9g=4g+4r

\Rightarrow 5g=4r\quad \ldots(i)

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}

\Rightarrow 10g+10r+60=23g+46

\Rightarrow 10r+14=13g\ quad \ldots(ii)

Substitute the value of g in equation (ii)[/tex]

\Rightarrow 10\times \frac{5}{4}g+14=13g

\Rightarrow \frac{25}{2}g+14=13g

\Rightarrow g=28

Therefore r=35

Thus there 28 green counter and 35 red counter

6 0
3 years ago
The number of kilograms of water in a human body varies directly as the mass of the body. A 72 kg person contains 48 kg of water
Tanzania [10]

Step-by-step explanation:

N=km

72=k×48

72=48k

k=72/48

k=1.5

N=1.5m

N=1.5×144

N=216

3 0
2 years ago
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stiks02 [169]
Do you have a typo? ;  < this maybe
4 0
3 years ago
Please help fast.
podryga [215]

\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

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8 0
3 years ago
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