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ella [17]
3 years ago
5

Someone please help me

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0
V=<span>πr^2 h/3
V=</span><span>π(3)^2 (4)/3
V=37.7 yd^3 or 36 yd^3</span>
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Read 2 more answers
The average value of two positive numbers is 30% less than one of the two numbers. By which percentage is average value bigger t
Viefleur [7K]

Answer:

75% bigger

Step-by-step explanation:

Let the first number be x and the second be y.

So:

Average = \frac{x + y}{2}

And:

Average = (1 - 30\%) * x -----30% less than x

Substitute Average = (1 - 30\%) * x in Average = \frac{x + y}{2}

\frac{x + y}{2} = (1 - 30\%) * x

\frac{x + y}{2} = (1 - 0.30) * x

\frac{x + y}{2} = 0.70 * x

\frac{x + y}{2} = 0.70x

Cross multiply

x + y = 0.70x * 2

x + y = 1.40x

Collect like terms

1.40x - x = y

0.40x = y

Make x the subject

x = \frac{y}{0.40}

x = 2.50y

So, the average is:

Average = (1 - 30\%) * x

Average = (1 - 30\%) * 2.50y

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Average =1.75y

Rewrite as:

Average =(1 + 0.75)y

Express as percentage

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This means that the average is 75% bigger than the second number

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