Answer:
Step-by-step explanation:
From the given information:
The uniform distribution can be represented by:

The function of the insurance is:

Hence, the variance of the insurance can also be an account forum.
![Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2](https://tex.z-dn.net/?f=Var%20%5BI_%7B%28x%7D%29%20%3D%20E%20%5BI%5E2%28x%29%5D%20-%20%5BE%28I%28x%29%5D%5E2)
here;
![E[I(x)] = \int f_x(x) I (x) \ sx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%20%5C%20dx)


Similarly;
![E[I^2(x)] = \int f_x(x) I^2 (x) \ sx](https://tex.z-dn.net/?f=E%5BI%5E2%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%5E2%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%5E2%20%5C%20dx)


∴
![Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]](https://tex.z-dn.net/?f=Var%20%7BI%28x%29%7D%20%3D%201250%5E2%20%5CBig%20%5B%20%5Cdfrac%7B5%7D%7B18%7D%20-%20%5Cdfrac%7B25%7D%7B144%7D%5D)
Finally, the standard deviation of the insurance payment is:


≅ 404
Answer:
The less the correlation between two variables means the more different their output is.
A.) If Rachel wants to diversify her investment by investing on bonds that do not closely follow the returns on the bond. then she should invest in the stocks with low correlation with bonds. I.e: small cap stocks.
B.) Similarly, due to low correlation, small cap bonds will increase ( comparatively to large cap bonds) as the return on her bonds wil drop and vice versa.
Answer:
The answer is 1.
Step-by-step explanation:
Answer:
17. y=1/2x+5
18. y=-2x+15
19. y=2x-7
Step-by-step explanation:
Number 17.
(4,7); parallel to y=1/2x-1
You know that lines that are parallel to each other have the same slope, so the slope is 1/2x.
1. Use the point-slope formula to solve for the slope-intercept equation.
y-y1=m(x-x1)
m= 1/2
x= 4
y= 7
y-7= 1/2(x-4)
y-7= 1/2x-2
y=1/2x+5
Number 18.
(4,7); perpendicular to y=1/2x-1
You know that lines that are perpendicular to each other have the opposite reciprocal slope, so the slope is -2.
1. Use the point-slope formula to solve for the slope-intercept equation.
y-y1=m(x-x1)
m= -2
x= 4
y= 7
y-7=-2(x-4)
y-7=-2x+8
y=-2x+15
Number 19.
f(3)=-1
f(4)=1
To write a linear equation, first find the slope with the slope formula.
x1= 3
y1= -1
x2= 4
y2=1
(y2-y1)/(x2-x1)
(1-(-1))/(4-3)
2/1
m=2
Use the point-slope formula and solve for the slope-intercept equation.
y-y1=m(x-x1)
y-1=2(x-4)
y-1=2x-8
y=2x-7
Answer:
He has 8 1/4 or 8.25 pounds of pearls
Step-by-step explanation:
4 3/4 + 3 1/2
You change 3 1/2 to 3 2/4 and then add them normal and change the improper fraction to a mixed number.