Answer:
B.
Step-by-step explanation:
Total coins = 11 ( 3 + 4 + 4 = 11).
The probability of picking a nickel first = 3/11 ( 4 nickels out of 11 total).
The probability of picking a dime second = 4/10 = 2/5 ( 3 dimes out of 10 coins left).
The probability of picking the third coin as a quarter = 4/9 ( 3 quarters out of 9 coins left).
The probability of picking all three in that order = 3/11 x 2/5 x 4/9 = 8/165
Y: x-1 that is the answer. I think so.
I = PRT
14,300 = (700)(0.0725)(t)
14,300 = 50.75(t)
14300/50.75 = t
281.77 = t or t = 281.77
hope this helps :)
Tha answer for the problem is 9,432
<span>−4(3−1)+2
=</span><span>−4(2)+2
= -8 + 2
= -6</span>