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2 years ago

X-2/x+1 > 0, what si da solution set?

Mathematics

2 answers:

sergejj [24]2 years ago

8 0

Answer:

u need to have better grammer

Step-by-step explanation:

yuradex [85]2 years ago

5 0

Answer:

(-∞ , -1) ∪ [ 2 , +∞)

Step-by-step explanation:

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2 3/4 divided by 4 1/8

DochEvi [55]

Answer:

2/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago

The city is planning to add a fish pound to a neighborhood park. the figure below is a scale drawing of the fish pound. its scal

CaHeK987 [17]

Answer: Sorry if it's wrong I hope I helped you

5 0

1 year ago

Please guys help please

almond37 [142]

Wild guess a I’m only guessing

4 0

2 years ago

Calculate the slope of the points (-2, -1) and (3, 4). Show all of your work.

puteri [66]

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{4 - (-1)}{3 - (-2)} = \frac{4 + 1}{3 + 2} = \frac{5}{5} = 1$

y - y₁ = m(x - x₁)
y - 4 = 1(x - 3)
y - 4 = 1(x) - 1(3)
y - 4 = x - 3
+ 4 + 4
y = x + 1

4 0

2 years ago

Read 2 more answers