Answer:
![r=\sqrt[3]{\frac{3v}{4} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3v%7D%7B4%7D%20%7D)
Step-by-step explanation:
To solve for 
:
(given)
(times 
on both sides)
I hope this helps :)
Answer:
4 times 4 equals 16
Step-by-step explanation:
4 times 1= 4
4 times 2= 8
4 times 3= 12
4 times 4= 16
you add 4 after each result.
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
1 to 5 you most likely have to add 36 x the number but the fractions I don't know
